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Mathematics

2 answers:

V125BC [204]2 years ago

7 0

First, every time when you ask question like this about function you must give elements of the initial set.

Definition of the function is - Every element of the starting set (domain- x)

must be related to only one element of the second set ( codomain-range-y).

In your case you have element (coordinate) x=3 which is in the relation with two elements (coordinates) y=2 and y=5 and that is relation but not function.

Good luck!!!

yawa3891 [41]2 years ago

6 0

The answer to your question is,

No. It is not a function. Reasoning behind this is because there are repeating numerators. You can NOT have two of the same numerator as that will not form correctly if graphed. Two threes.

-Mabel <3

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A family is driving from Phoenix to San Francisco. On a map grid, Phoenix is located at (–12, –16), and San Francisco is located

makkiz [27]

The answer is 34.05

The total distance (D) is the sum of three distances (d1, d2, and d3).

The distance formula is $d = \sqrt{(x2-x1)^{2} +(y2-y1)^{2}}$

Distance 1: Phoenix (–12, –16) to Blythe (–20, –9):
 $d1 = \sqrt{(-20-(-12))^{2} +(-9-(-16))^{2}} =\sqrt{(-20+12)^{2} +(-9+16)^{2}} \\ =\sqrt{(-8)^{2} +(7)^{2}}= \sqrt{64+49} = \sqrt{113}= 10.63$

Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
$d2 = \sqrt{(-33-(-20))^{2} +(-4-(-9))^{2}} =\sqrt{(-33+20)^{2} +(-4+9)^{2}} \\ =\sqrt{(-13)^{2} +(5)^{2}}= \sqrt{169+25} = \sqrt{194}= 13.93$

Distance 3: Los Angeles (–33, –4) to San Francisco (–36, 5)
 $d3 = \sqrt{(-36-(-33))^{2} +(5-(-4))^{2}} =\sqrt{(-36+33)^{2} +(5+4)^{2}} \\ =\sqrt{(-3)^{2} +(9)^{2}}= \sqrt{9+81} = \sqrt{90}= 9.49$

D = d1 + d2 + d3 = 10.63 + 13.93 + 9.49 = 34.05

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