Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
I think it’s four. If not then I’m sorry
Answer: Hello your question some data but i will provide a general solution based on the scope of your question making some suggestions as well
answer : Summation of displacements ( back and forth distance ) / Number of Runners
Step-by-step explanation:
Given that ; the aim of the race is to raise money
The number of miles/ distance covered will determine how much money that would be raised
Formula to resolve the problem = Summation of displacements ( back and forth distance ) / Number of Runners
<em>Lets assume: ( example ) </em>
<em> Distance between the Park and the City hall is = 6 miles </em>
<em>Number of runners = 4</em>
<em>Given that the runners Run from the Park to the City hall and then run back</em>
<em>Total miles covered by each runner = ( 6 + 6 )/ 4 = 12/4 = 3 miles </em>
Answer:
No :)
Step-by-step explanation:
the graph does not make a straight line. :)
