The degree is 3, the zeros are; 4, 2i, -2i and a point is (-48, 2)
For zeros; 2i, -2i <-- complex conjugates, always in pairs

= -4(i²=-1)
=5

=0
Therefore the equation is; a(

+5) <-- b value is zero
Rewrite the equation with all zeros;
a(x-4)(x²+5)=f(x) <-- put in coordinates of the points to find the value of x
a(2-4)(2²+5)=-48
a(2)(9)=-48
a=-48/18
a=-8/3
The final polynomial function is; (-8/3)(x-4)(x²+5)=f(x)
Hope I helped :)
Answer:

Step-by-step explanation:
In order to solve this, we are trying to find the value of
. Basically,
is a placeholder for a number that is unknown. Some number minus 3 is equal to 21.
Our goal is to find
. To do this we want to isolate
on one side of the equation

Let's add 3 to both sides.

Hope this helped!
Answer:
w=12 or w=2
Step-by-step explanation:
2w^2-16w=12w-48
2w^2-28w=-48
2w^2-28w+48=0
2(w^2-14w+24)=0
2(w-12)(w-2)=0
(w-12)(w-2)=0
w=12 or w=2
Answer:
The third one
Step-by-step explanation:
It transitions into the negative x
Answer:
cant say you dont show
Step-by-step explanation:
id love to help but like send a picture next time