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mamaluj [8]
3 years ago
12

The sloped roof of a house that is right beside its property line can be represented by the inequality −|x − 2| + 9 > 6. Solv

e and graph the solutions of the inequality to show the horizontal position of the roof, relative to the property line. THIS IS A WHOOLE LOT A POINTS, PLEASE ANSWER.

Mathematics
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

This Is CORRECT

Step-by-step explanation:

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ed is using the recipe shown to make fruite salad 4 bananas diced 3 apples diced 6 pears diced 10 strawberries diced he wants to
Nastasia [14]
In the original recipe, it asks for 10 diced strawberries. 10x3=30, so for all of the required numbers of fruits, multiply the number by three. 4x3=12 bananas 3x3=9 apples 6x3=18 pears 10x3=30 strawberries
3 0
3 years ago
Which type of relationship would best model this data?
MAXImum [283]

Answer:

positive linear is correct answer

6 0
3 years ago
Two sizes of cans of beans are similar. The thickness of the walls and bases are the same in both cans. The ratio of their surfa
agasfer [191]

Answer:

It costs  $0.216  to make smaller can and $0.324 to make larger can

Step-by-step explanation:

Given:

The ratio of the surface areas = 4:9

Area of smaller cans =  36 sq in

Cost  = $0.006 per square inch  

To Find:

how much does it cost to make each can = ?

Solution:

Lets the area of the larger can be x

the ratio is  4 :  9

then 4x =  9.(36)

4x = 216

x = \frac{216}{4}

x =  54

The area of the larger can is 54 sq in

Now the cost of making the smaller can  =   36 \times  0.006 = $0.216

The cost of making the Larger can = 54 \times 0.006 =$0.324

4 0
3 years ago
Todea what did one pencil say to another mathematics algebra order of operations answer
Serjik [45]
Part 1

6- \frac{18-3^2}{4+(2-3)} =6- \frac{18-9}{4+(-1)}  \\  \\ =6- \frac{9}{4-1} =6- \frac{9}{3} =6-3 \\  \\ =3



Part 2

7-8\div4(3^2-1)=7-8\div4(9-1) \\  \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\  \\ =6  \frac{1}{2} = \frac{13}{2}



Part 3

2-2(2-5)^2+3^2=2-2(-3)^2+9 \\  \\ =2-2(9)+9=2-18+9=-7



Part 4

(5^2-9\cdot3)^2-11=(25-27)^2-11 \\  \\ =(-2)^2-11=4-11=-7



Part 5

[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\  \\ =(1-5)\cdot4=-4\cdot4=-16



Part 6

12-11\cdot2+16\div8=12-22+2 \\  \\ =-8



Part 7

-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\  \\ =-2-(-1)=-2+1=-1



Part 8

8+2\cdot3-14\div7=8+6-2 \\  \\ =12



Part 9

(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\  \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\  \\ =36+4=40



Part 10

7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\  \\ =7+(-7)\cdot5=7+(-35)=7-35 \\  \\ =-28



Part 11

3-2[2^3+(-1)^3]=3-2[8+(-1)] \\  \\ =3-2(8-1)=3-2(7)=3-14 \\  \\ -11



Part 12

18+6\div3(2^2+5)=18+6\div3(4+5) \\  \\ =18+6\div3(9)=18+6\div27=18+ \frac{2}{9} \\  \\  =18 \frac{2}{9}
8 0
3 years ago
How do I Graph y=  –73x+2 .
Romashka-Z-Leto [24]

Answer:

See attachment

Step-by-step explanation:

You can obtain any two points on the graph of y=-73x+2 and use it to draw its graph.

When x=0, y=-73*0+2=2

So you plot (0,2)

When x=1, y=-73*1+2=-71

You again plot (1,-71).

With a straight edge you can now draw a straight line through the two points.

See attachment

4 0
3 years ago
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