Answer: the answer is 7.5
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
Linear means a line, and x is not squared or anything in this equation. If you were to graph it, it would be a line.
Answer:
![\sqrt{74}](https://tex.z-dn.net/?f=%5Csqrt%7B74%7D)
Step-by-step explanation:
<u>Distance between two points</u>
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
![\textsf{let}\:(x_1,y_1)=(2,-6)](https://tex.z-dn.net/?f=%5Ctextsf%7Blet%7D%5C%3A%28x_1%2Cy_1%29%3D%282%2C-6%29)
![\textsf{let}\:(x_2,y_2)=(7,1)](https://tex.z-dn.net/?f=%5Ctextsf%7Blet%7D%5C%3A%28x_2%2Cy_2%29%3D%287%2C1%29)
![d=\textsf{length of segment AB}](https://tex.z-dn.net/?f=d%3D%5Ctextsf%7Blength%20of%20segment%20AB%7D)
Substituting points into the distance formula and solving for d:
![\implies d=\sqrt{(7-2)^2+(1-(-6))^2}](https://tex.z-dn.net/?f=%5Cimplies%20d%3D%5Csqrt%7B%287-2%29%5E2%2B%281-%28-6%29%29%5E2%7D)
![\implies d=\sqrt{5^2+7^2}](https://tex.z-dn.net/?f=%5Cimplies%20d%3D%5Csqrt%7B5%5E2%2B7%5E2%7D)
![\implies d=\sqrt{25+49}](https://tex.z-dn.net/?f=%5Cimplies%20d%3D%5Csqrt%7B25%2B49%7D)
![\implies d=\sqrt{74}](https://tex.z-dn.net/?f=%5Cimplies%20d%3D%5Csqrt%7B74%7D)
Answer:
2884.8 millimeters squared
Step-by-step explanation:
Given:
The radius of the disc is 35 millimeters, so the area of it is:
π
= 3.14*
= 3846.5
Then, we find out the area of the circular hold cut out of the bigger one, its radius is a haft of the radius of the bigger circle = 35/2 = 17.5
π
= 3.14*
=961.6
=> the area of the pendant = 3846.5 - 961.6 =2884.8 millimeters squared
Answer:
24 degrees
Step-by-step explanation:
2b=180^o-132^o
2b=48^o
b=24^o