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Volgvan
3 years ago
11

Pls somebody can help me? What is the domain of f(x) = (1/2)^x ?

Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0

Answer:

C. All real numbers

Step-by-step explanation:

x goes forever in both the positive and negative directions, so the domain is all real numbers.

lana [24]3 years ago
3 0

Answer:

all real numbers

Step-by-step explanation:

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Which statement best explains the relationship between
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Answer:

The best statement which explains the relationship between lines AB and CD is "They are parallel because their slopes are equal" ⇒ A

Step-by-step explanation:

  • Parallel lines have equal slopes and different y-intercepts
  • The rule of the slope of a line passes through points (x1, y1) and (x2, y2) is m = \frac{y2-y1}{x2-x1}

In the given figure

∵ The blue line passes through points A and B

∵ A = (-4, -2) and B = (4, 4)

∴ x1 = -4 and y1 = -2

∴ x2 = 4 and y2 = 4

→ Substitute them in the rule of the slope

∵ m(AB) = \frac{4--2}{4--4} = \frac{4+2}{4+4} = \frac{6}{8} = \frac{3}{4}

∴ The slope of line AB is  \frac{3}{4}

∵ The green line passes through points C and D

∵ C = (0, -3) and D = (4, 0)

∴ x1 = 0 and y1 = -3

∴ x2 = 4 and y2 = 0

→ Substitute them in the rule of the slope

∵ m(CD) = \frac{0--3}{4-0} = \frac{0+3}{4} = \frac{3}{4}

∴ The slope of line CD is  \frac{3}{4}

∵ The slope of line AB = the slope of line CD

∵ Parallel lines have the same slope

∴ AB // CD

∴ AB and CD are parallel lines

The best statement which explains the relationship between lines AB and CD is "They are parallel because their slopes are equal"

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Step-by-step explanation:

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Derive these identities using the addition or subtraction formulas for sine or cosine: sinacosb=(sin(a+b)+sin(a-b))/2
Sergeu [11.5K]

Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b).

The sine difference identity is:

\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a).

The cosine addition identity is:

\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b).

The cosine difference identity is:

\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b).

We need to find a way to put some or all of these together to get:

\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}.

So I do notice on the right hand side the \sin(a+b) and the \sin(a-b).

Let's start there then.

There is a plus sign in between them so let's add those together:

\sin(a+b)+\sin(a-b)

=[\sin(a+b)]+[\sin(a-b)]

=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]

There are two pairs of like terms. I will gather them together so you can see it more clearly:

=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]

=2\sin(a)\cos(b)+0

=2\sin(a)\cos(b)

So this implies:

\sin(a+b)+\sin(a-b)=2\sin(a)\cos(b)

Divide both sides by 2:

\frac{\sin(a+b)+\sin(a-b)}{2}=\sin(a)\cos(b)

By the symmetric property we can write:

\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}

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Alayna worked 44 hours last week. Her hourly rate is $9.00. Alayna’s gross pay for last week was $
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Answer:

$396

Step-by-step explanation:

Alayna's hourly rate (or pay per hour) is $9.

She worked 44 hours in total last week. To solve, multiply 44 with 9

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