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Virty [35]
3 years ago
12

Quadrilateral ABCD is similar to Quadrilateral EFGH. The scale factor is 3:2. If AB = 18, find EF.

Mathematics
2 answers:
nasty-shy [4]3 years ago
6 0
The answer is A. 12

do you want to know how I got my answer...
meriva3 years ago
5 0

Answer: 12

Step-by-step explanation: The correct answer is 12. This problem can be solved by setting up a proportion and cross multiplying.

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2 1/2 ÷ 1 5/8 =<br><br> Two and a half divided by one and five eights
LUCKY_DIMON [66]
So first of all we can't start by changing them both into improper fractions

So it would be:
5/2 divided by 13/8
From there you would do 5/2 * 8/13 which could convert to
5/1 * 4/13 which would be 20/13
3 0
3 years ago
Read 2 more answers
If angle 2 = 48, determine the measure of angle 5.
Hatshy [7]

Answer:

Angle 2 = 48

we are going to divide 48 by 2 to get the Angle 1

Angle 1 = 24

then Angle 5 = (5×24)

<em><u>Angle</u></em><em><u> </u></em><em><u>5</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>2</u></em><em><u>0</u></em>

6 0
3 years ago
jason and his family travels 160 miles in 3.2 hours. if they continue at this constant speed, how long will it take them to trav
Misha Larkins [42]
Set up a proportion 
160 mi/ 3.2 hrs ≈ 300 mi/x hrs
cross multiply and solve for x and you get x≈6
It will take them 6 hours

3 0
3 years ago
Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (2, 3)
lozanna [386]
Standard equation of a circle: <em>(x-h)² + (y-k)² = r²</em> where <em>(h, k)</em> is the center and <em>r </em>is the radius. In the case of our equation here, <em>(x-5)² + (y+3)² = 25</em>, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Distance = \sqrt{(-3-3)^2+(5-2)^2}

Distance = \sqrt{(-6)^2+3^2}

Distance = \sqrt{36+9}

Distance = \sqrt{45}\approx6.7082

6.7082>5,\ so\ (2,3)\ is\ on\ the\ \boxed{exterior}
8 0
3 years ago
How do you write 16% as a decimal​
ad-work [718]

Answer

Decimal Form: 0.16

Step-by-step explanation

♡ ∩_∩

(„• ֊ •„)♡

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♡ good luck。 ♡

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7 0
2 years ago
Read 2 more answers
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