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Virty [35]
3 years ago
12

Quadrilateral ABCD is similar to Quadrilateral EFGH. The scale factor is 3:2. If AB = 18, find EF.

Mathematics
2 answers:
nasty-shy [4]3 years ago
6 0
The answer is A. 12

do you want to know how I got my answer...
meriva3 years ago
5 0

Answer: 12

Step-by-step explanation: The correct answer is 12. This problem can be solved by setting up a proportion and cross multiplying.

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Can someone plz help me dont know the awnser
Bumek [7]
The area of the right triangle = \frac{1}{2}bh

b = base = SV = 12.3
h = hight = HL = 24.6
A = area
\frac{1}{2}bh = A
\frac{1}{2}(12.3)(24.6) = 151.29
4 0
3 years ago
O que são números racionais
Dmitrij [34]
<span>Números racionales son números que pueden ser wriiten como una proporción, y pueden ser escritos como una fracción también. Un ejemplo de un número racional sería dos cuartos (2/4), medio (1/2), etc.</span>
6 0
3 years ago
Tickets for a certain show cost ​$17​, ​$21​, ​or, for VIP​ seats, ​$40. If ten times as many ​$17 tickets were sold as VIP​ tic
lawyer [7]

Answer:

Tickets sold:

VIP =126

$17 tickets =1,260

$21 tickets =9\cdot 126+57=1,191

Step-by-step explanation:

Let x be the number of VIP tickets.  

If ten times as many ​$17 tickets were sold as VIP​ tickets, then the number of $17 tickets is 10x.

If the number of ​$17 tickets sold was 57 more than the sum of the number of ​$21 tickets and VIP​ tickets, then 10x+57=x+y and the number y of $21 tickets is 9x+57.

Amounts earned:

VIP tickets =\$40x

$17 tickets =\$17\cdot 10x=\$170x

$21 tickets =\$21\cdot (9x+57)=\$(189x+1,197)

Total =\$(40x+170x+189x+1,197)=\$(399x+1,197)

The sales of all three kinds of tickets would total ​$51,471, so

399x+1,197=51,471\\ \\399x=51,471-1,197\\ \\399x=50,274\\ \\x=126

Tickets sold:

VIP =126

$17 tickets =1,260

$21 tickets =9\cdot 126+57=1,191

8 0
3 years ago
How many ways can a person select 3 coins from a box consisting of a penny, a nickel, a dime, a quarter, a half dollar, and a on
tekilochka [14]

Answer:

A person can select 3 coins from a box containing 6 different coins in 120 different ways.

Step-by-step explanation:

Total choices = n = 6

no. of selections to be made = r = 3

The order of selection of coins matter so we will use permutation here.

Using the formula of Permutation:

                  nPr = \frac{n!}{(n-r)!}

We can find all possible ways arranging 'r' number of objects from a given 'n' number of choices.

Order of coin is important means that if we select 3 coins in these two orders:

--> nickel - dime - quarter

--> dime - quarter - nickel

They will count as two different cases.

Calculating the no. of ways 3 coins can be selected from 6 coins.

nPr = \frac{n!}{(n-r)!} = \frac{6!}{(6-3)!}

nPr = 120

6 0
3 years ago
PLS HELP I WILL MARK BRAINLIST
Likurg_2 [28]

Answer: B. 0 ≤ x ≤ 4

Step-by-step explanation: Have a nice day bro!✌️

8 0
3 years ago
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