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Lilit [14]
3 years ago
15

Write the equation of a line ( slope intercept form y = mx + b)

Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

y=1/4x-1

Step-by-step explanation:

i knew the general equation of the line and i knew the slope would be a fraction because the line is rlly flat

-1 would be the b and i plugged in simple fraction values for m

i checked in desmos and they look similar

hope this helps and is correct <3

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A tablet weighs 1.23 pounds. What is its weight written as a mixed number?
garik1379 [7]
If a tablet weighs 1.23 pounds, the weight written as a mixed number would be, 1 as the whole number and 23 is in the hundreds place, so you would write, 1 and 23/100.
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Which products are greater than 256? Choose all that apply.
Novay_Z [31]
257 is the answer to this question
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Are both 7 and -½ integers? why or why not?​
Tems11 [23]

Answer:

No. (-1/2) is not an integer

Integers involve all the no. +ve and -ve. which can be written without fraction. ie whole no. are counted as integers.

(-1/2) is a fraction

4 0
1 year ago
Read 2 more answers
One-Half of a number increased by 6 is less than 34
Vlada [557]

Answer: ½ x + 6 < 34 ; x < 56

Step-by-step explanation:

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  2. Divide ½ on both sides. x < 56.
3 0
2 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
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