Ask question

Ask question

All categories

3 years ago

14

Factor out the common terms 2x+4y

2 answers:

seraphim [82]3 years ago

5 0

Answer:

Step-by-step explanation:

2x = 2*x

4y = 2*2*y

Common term = 2

2x + 4y = 2*x + 2*2y

=2*(x + 2y)

notka56 [123]3 years ago

3 0

^^^ but you should download photomath

You might be interested in

According to the lecture, a valedictory speech should last approximately ________ minutes.

fiasKO [112]

<span>According to the lecture, a valedictory speech should last approximately 15 minutes. </span>

6 0

3 years ago

The unbalanced wheel has a mass of 15 kg and rolls without slipping on the flat horizontal surface. The wheel has a radius of gy

miv72 [106K]

Answer:

a) $a_w=4.331m/s^2$

b) $F=53.7N$

c) $\mu=96.5N$

Step-by-step explanation:

From the question we are told that

mass of unbalanced wheel $M=15kg$

Radius of gyration $G=64m$

Mass center $M_c =40mm=$ $4*10^{-2} m$

Angular velocity $\omega=4rads/s$

a)

Generally the equation for moment at point A is mathematically given as

$\sum M_a=I \alpha+\sum M \=ad$

Where $a_w=wheel\ accelaration$

$15*9.81*(0.04)=0.06144*\frac{a_w}{0.1}+15(0.04)(0.04)\frac{a_w}{0.1}+(15a_w-15(0.04)(4^2)0.1)$

$5,87=(a_w*0.8544+15a_0-0.96)$

$a_w=4.331m/s^2$

b)

Generally the equation for equilibrium of system on the horizontal axis is mathematically given as

$\sum f_x=ma_w$

$F=ma_w-m \=r w^2$

$F=(25*4.221)-(15*0.04*4^2)$

$F=63.3-9.6$

$F=53.7N$

c)

Generally the equation for equilibrium of system on the vertical axis is mathematically given as

$\sum f_y=ma_w$

Where

$F=\mu-mg+m \=r \alpha$

$\alpha=\frac{a_0}{0.1}$

$\mu-mg+m \=r \alpha=0$

$\mu-15*9.81+15*0.04*\frac{4.221}{0.1}$

$\mu-96.5N=0$

$\mu=96.5$

3 0

3 years ago

Light travels at 3.0×10^8 kilometers how far does light travel in five minutes

34kurt

Just have a very grate day

8 0

3 years ago

Can you guys help me

vlada-n [284]

The answer is a have a great day/night !

5 0

3 years ago

What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

7 0

4 years ago

Read 2 more answers