The second one is the correct answer.
(For question 1 you have to do it yourself, get a ruler and measure the actual length of the drawing, then multiply it by 8 to get the actual dimensions in the exercise. )
Example, if you measure 4 inches, the actual dimension will be 4 x 8 = 32 ft
2. (Scale drawing 1:5 is that every 1 (length units) will be equal to 5(length units) in the actual dimensions)
Model : 3ft ; 7m
Actual : 15ft ; 35m (corresponding)
Actual : 20yd ; 12.5 cm
Model : 4yd ; 2.5 cm
6. 1.5 ft = 1.5 x 12 = 18 inches.
The model is 3 inches, and the actual rose is 18 inches -> The scale of the drawing is 6. (enlargement)
Same goes to the scale factor, but this time is the quotient of the corresponding side -> 3 : 18 = 1:6.
(If I got any parts wrong just tell me, I actually kinda forgot these kind of stuff)
Answer yes
Step-by-step explanation:
Answer:
A) 10.38hours
B) 617.95 is the concerntration of CO
Step-by-step explanation:
A) when x=600
T= 0.0002x^2 - 0.316x + 127.9
T= 0.0002(600)^2 -0.316(600) + 127.9
T= 10.38secs
B) to find the concerntration, use Almighty formular
X=-b+-sqrt(b^2-4ac)/2a
0.0002x^2-0.316x-127.9=9
0.0002x^2 - 0.316x + 118.9=0
X= 0.316 +- sqrt(0.316^2) -4(0.0002×118.9)/(2×0.0002)
X= 0.316+(0.68817/0.0004)=962.05 or
X=-0.316 -0.68817/0.0004 =617.95
Therefore X is within the domain of 617.95 is the concerntration
