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Free_Kalibri [48]
3 years ago
9

a container is 24m long ,9m wide and 8m high. How many books can it hold if each book is 20cm long, 16cm wideand 6cm thick

Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

900,000 books

Step-by-step explanation:

book is a three dimensional object there you need to find the ratio of the container to the book. ( units must be the same)

Vcontainer=length*width*height

Vcontainer=2400cm*900cm*800cm

Vcontainer=1,728,000,000cm^3

Vbook=length*width*height

Vbook=20cm*16cm*6cm

Vbook=1920cm^3

no books =Vcontainer/Vbook

no books =1,728,000,000cm^3/1920cm^3

no books=900,000 books

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3 years ago
The length of a rectangle field is represented by the expression 14 X minus 3X squared +2 Y. The width of the field is represent
Assoli18 [71]

Answer:

9x+4x^2-5y

Step-by-step explanation:

Hi there!

Length of the field: 14x-3x^2+2y units

Width of the field: 5x-7x^2+7y units

To find how much greater the length of the field is than the width, subtract the width from the length:

14x-3x^2+2y-(5x-7x^2+7y)

Open up the parentheses

= 14x-3x^2+2y-5x+7x^2-7y

Combine like terms

= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y

Therefore, the length is 9x+4x^2-5y units greater than the width.

I hope this helps!

7 0
3 years ago
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astra-53 [7]
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(sin^2x/cosx)*sinx   (where 1-cos^2x=sin^2x) and 1/cscx=sinx

sinx/cosx=tanx(divide by sinx)
hence proved
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