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3 years ago

Can someone help me please

Mathematics

1 answer:

koban [17]3 years ago

6 0

it is 87 inches since there are 12 inches in a foot and there are 7. Multiply 7 and 12 to get 84 then add 3 = 87

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What is the mean of 4,6,7,7,11,12,15,18,20

ExtremeBDS [4]

Answer:

Step-by-step explanation:

4+6+7+7+11+12+15+18+20= 100

divide by the number of values we have. we have 9 values

100/9=11.1111111111

I hope this helped

4 0

3 years ago

Read 2 more answers

A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t

xz_007 [3.2K]

Full Question

A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.

Determine the spring constant k.

Answer:

Spring Constant = 1000Nm^-1

Step-by-step explanation:

Given

Mass = 10kg

Spring Extension = 9.8cm

Spring Constant K = Force/Extension

Force = Mass * Acceleration

Force = 10 * 9.8 = 9.8N

Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m

Spring constant = 98 / 0.098

Spring Constant = 1000Nm^-1

3 0

3 years ago

What is the difference between 4 and 62<br> 2.

Naddik [55]

Answer:

6214

Step-by-step explanation:

you round up 62 and 4 20 times and that is your answer but for give me if this answer wrong

4 0

3 years ago

A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The

Oksanka [162]

Answer:

a) $[-0.134,0.034]$

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

$s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2}$ ,

where $n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19$ .

The mean difference $\mu_1 - \mu_2 = 10.85 - 10.90 = -0.05$ .

The confidence interval is

$(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}$

$= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]$

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0

3 years ago

Please helppp!!<br> For the equation y = 3x – 6 Complete the table for the x values given.

enot [183]

Answer:

Step-by-step explanation:

y = 3x -6

x = -2, y = -12

x = -1, y = -9

x = 0, y = -6

x = 1, y = -3

x = 2, y = 0

x= 3, y = 3

x -2 -1 0 1 2 3

y -12 -9 -6 -3 0 3

6 0

3 years ago