There are 25 species of trees, each with a known abundances. The question is how many possible ways to randomly select one tree there are.
We should calculate the number of combinations. Combinations, because we select item/s from a collection. In this case, when we select only one item, the combination is also a permutation. From set of n objects we select r. In our case: n=25, r=1.
The equation is: n!/r!(n-r)!= 25!/1!*24!=25*24!/24!=25
There are 25 different outcomes (events).
Answer:
b. the ranges of penguin heights are the same.
Step-by-step explanation:
Hello!
Statements:
Which statement correctly compares the spreads of the distributions?
a. the mode of penguin heights at county side zoo is greater than the mode at city view zoo.
b. the ranges of penguin heights are the same.
c. the range of penguin heights is greater at city view zoo than at county side zoo.
d. the range of penguin heights is greater at county side zoo than at city view zoo.
The mode and mean are measurements of central tendency, these indicate the position of a data set but don't show any information concerning the distribution of said data.
The range on the other had is a measurement of variance, it shows the difference between the maximum and minimum values of the data set and indicates its total dispersion.
City view Zoo R= 44-37= 7 cm
County side Zoo: R= 45-38= 7 cm
Both ranges are the same.
I hope this helps!
Answer: 5 benches and 23 students
Step-by-step explanation:
I will answer in English.
We have E students and B benches.
If we sit 4 students per bench, we have 3 students left.
then:
E = 4*B + 3
And if we sit 5 students per bench, there are two places with no students sited.
E = 5*B - 2
now we can replace the E in the second equation with the right part in the first equation:
4*B + 3 = 5*B - 2
3 + 2 = 5*B - 4*B
5 = B
So we have 5 benches, and:
E = 4*5 + 3 = 23 students.
Answer:
20 cm
Step-by-step explanation:
Equilateral means the sides are congruent.
6cm + 6cm + 8cm = 20cm