Which set of ordered pairs does NOT represent a function?
1 answer:
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Answer:
= 2
= k(k+1)
= (k+1)(k+2)
Step-by-step explanation:
We are given the statement,
as 2 + 4 + 6 + . . . + 2n = n(n+1)
That is,
as 2 + 4 + 6 + . . . + 2n =
So, we have,
=
= 2
=
= 2 + 4 + 6 + . . . + 2k = k(k+1)
=
= 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)
Thus, we get,
= 2
= k(k+1)
= (k+1)(k+2)
Answer:
Option D:
Step-by-step explanation:
Differential equation:
For the population in function of the time, is:
The population P of rabbits on a small island grows at a rate that is jointly proportional to the size of the rabbit population and the difference between the rabbit population and the carrying capacity of the population
Carring capacity is 2400.
This means that the differential equation is kP(size of the population multiplied by the constant) multiplied by 2400 - P(difference between the population and the carrying capacity). So
So the answer is given by option D.