Question

How do you solve this

Answer 1

Simple...

you have: $2x^{2} -9x+16=6$

To even begin, set all terms to the left side and set the parabola equal to zero-->>

$2x^{2} -9x+10$

Now, you can factor!

What multiplies to 20 and adds to -9?

-5*-4=20

-5+-4=-9

Then, using the box method...

x=$\frac{5}{2} ,2$

Thus, your answer.

Answer 2

2x^2 - 9x + 16 = 6
2x^2 - 9x + 16 - 6 = 0
2x^2 - 9x + 10 = 0
(2x - 5)(x - 2) = 0

2x - 5 = 0
     2x = 5
       x = 5/2
       x = 2.5

x - 2 = 0
     x = 2

answer x = 2 and x = 2.5