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Fudgin [204]
3 years ago
7

I wish someone could love me just like how someone use to

Mathematics
1 answer:
tatiyna3 years ago
3 0

Answer:

me too bro me too........

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Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1
Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(c) 0.0039

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

P(x=r)=^nC_rp^rq^{n-r}

(a) Exactly two will be drunken drivers.

P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}

P(x=2)=66(0.2)^{2}(0.8)^{10}

P(x=2)=\approx 0.28347

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)

P(x=3\text{ or }x=4)=P(x=3)+P(x=4)

Using binomial we get

P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}

P(x=3\text{ or }x=4)=0.236223+0.132876

P(x=3\text{ or }x=4)\approx 0.369099

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

P(x\geq 7)=1-P(x

P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]

P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]

P(x\leq 7)=1-[0.9961]

P(x\leq 7)=0.0039

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)

P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315

P(x\leq 5)=0.9806

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0
3 years ago
HELP I NEED TO DO THIS BY TODAY
Fudgin [204]

Answer:

I can't see the picture.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Given Δ XYZ ≅ Δ EGF, find the measurements of the unknown sides and angles.
mamaluj [8]
The two triangles are similar and equal therefore; It means the corresponding sides are equal and the corresponding angles are equal. Hence;
 ZX=EF, thus,ZX = 1.3 in. 
EG = XY, thus, EG = 3.0 in.
m∠ X = m∠E, thus m ∠X = 48°
m∠ G = m∠Y, and angles in a triangle add up to 180 thus;
  m ∠ G=180- (107 +48) = 25°

6 0
3 years ago
Read 2 more answers
Someone please help me with #2
mario62 [17]

<em>Good luck, you'll need it :)</em>

6 0
3 years ago
Evaluate ∫ xe2x dx. 1 2 3x A./xe +C 6 B.1/xe2x-1/ xe2x+C 22 C.1/xe2x-1/ e2x+C 24 1 2 1 4x D./x-/e +C 28
Dafna1 [17]
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C

Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
     u = x
     dv/dx = e^(2x)

By differentiating u, we get
     du/dx= 1
By integrating dv/dx= e^(2x), we have
     v =∫e^(2x) dx = (1/2)e^(2x)

Then we substitute these values to the integration by parts formula:
     ∫ u(dv/dx) dx = uv −∫ v(du/dx) dx 
     ∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
                          = (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
                          = (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.

Therefore, 
     ∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
7 0
4 years ago
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