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Gnom [1K]
2 years ago
11

A car rents for $45 per day plus .22cent toy are on a daily budget of 77 what mialage

Mathematics
1 answer:
elena55 [62]2 years ago
4 0
If its $45 per day plus $0.22 cents, and you only have $77. You can only have the car for 1.7 days which adds up too $76.94.
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A student is trying to calculate the density of a ball. She already knows the mass, but she needs to determine the volume as wel
mario62 [17]
<h2>Answer and Explanation:</h2><h2 />

The density of a substance is defined as its mass per unit volume. In a mathematical language, this can be written as follows:

\rho=\frac{m}{V} \\ \\ \\ Where: \\ \\ \rho: \ density \\ \\ m:mass \\ \\ V:Volume

From the problem, a student is trying to calculate the density of a ball. She already knows the mass, but is facing a problem because she also needs to find the volume. From geometry, we know that the volume of a sphere is:

V=\frac{4}{3} \pi r^{3}

Since a ball is a sphere, then the student can use this formula. She just need to measure the radius of the ball and compute the Volumen, then she have to plug both the value of the mass and the value of the Volume in the equation \rho=\frac{m}{V}. An easy way to find the radius is to take the measure of the diameter of the ball and divide that value by 2.

6 0
3 years ago
Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1).
Marina86 [1]

Given:

The given equation is:

y=-4x+3

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

y=mx+b

Where, m is slope and b is y-intercept.

We have,

y=-4x+3

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

m\times (-4)=-1

m=\dfrac{-1}{-4}

m=\dfrac{1}{4}

The slope of required line is m=\dfrac{1}{4} and it passes through the point (4,-1). So, the equation of the line is:

y-(-1)=\dfrac{1}{4}(x-4)

y+1=\dfrac{1}{4}(x)-\dfrac{4}{4}

y=\dfrac{1}{4}x-1-1

y=\dfrac{1}{4}x-2

Therefore, the equation of the required line is y=\dfrac{1}{4}x-2.

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