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IrinaK [193]
3 years ago
10

Give an example of a rational function that has a horizontal asymptote at y = 1 and a vertical asymptote at x = 4.

Mathematics
1 answer:
Greeley [361]3 years ago
4 0

Answer:

Possibility 1: \frac{(x+1)(x+1)}{(x-4)(x+5)}

Possibility 2: \frac{(x+1)(x+3)(x-3)}{x(x-4)(x+5)}

Possibility 3: \frac{-4(x-4)(x+1)}{-4(x-4)(x-4)}

There are infinitely many more possibilities.

Step-by-step explanation:

So we are looking for a fraction in terms of x.

We have a horizontal asymptote so that means the degree of the top has to equal to degree of the bottom. It is also at y=1 which means the coefficient of the leading term on top and bottom must be the same (but not zero) since the same number divided by the same number is 1.  

Now we also have a vertical asymptote at x=4 which means we need a factor of x-4 on bottom.

So there is a lot of possibilities. Here are a few:

Possibility 1: \frac{(x+1)(x+1)}{(x-4)(x+5)}

You have the degrees are the same on top and bottom and the leading coefficients are the same.  You also have that factor of (x-4) on bottom.

Possibility 2: \frac{(x+1)(x+3)(x-3)}{x(x-4)(x+5)}

Possibility 3: \frac{-4(x-4)(x+1)}{-4(x-4)(x-4)}

Now a factor of (x-4) can be canceled here but you still have a factor of (x-4) left on bottom so you still have the vertical asymptote. You also still have the same leading coefficient on top and bottom (-4 in this case) and the same degree.

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Answer: C

Step-by-step explanation: Consider a triangle with points A, B and C. You must create a perpendicular bisector of AB and then a perpendicular bisector of BC that crosses each other. Then you must label the center of that point D, and then using a compass tool, create a circle around the triangle.

8 0
2 years ago
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, list the first five terms of each sequence, and identify them as arithmetic or geometric.
Serhud [2]

Answer:

The first 5 terms are -6,-25,-44,-63 and -82

The sequence is arithmetic

Step-by-step explanation:

Given that A(n + 1) = A(n) − 19 for n ≥ 1 and A(1) = −6

A(1) = -6

A(2) = A(1) − 19 = -6 - 19 = -25

A(3) = A(2) − 19 = -25 - 19 = -44

A(4) = A(3) − 19 = -44 - 19 = -63

A(5) = A(4) − 19 = -63 - 19 = -82

So the first 5 terms are -6,-25,-44,-63 and -82

If they are in arithmetic the common difference will be same, if geometric common ratio will be same.

Let us check common difference,

                       -25-(-6) = -19

                       -44-(-25) = -19

                       -63-(-44) = -19

                       -82-(-63) = -19

So common difference is same, so the sequence is arithmetic.

3 0
3 years ago
A knife is three times the cost of a spoon. 9 spoons and 12 knifes cost ?82.80 workout the cost of 1 knife.
tankabanditka [31]

Let S = spoon

Let K = knife


1 knife is thee times the cost of a spoon, so it would be 3S

Now you have 9S + 12K = 82.80

We can replace the K with 3S:

9S +12(3S) = 82.80

Simplify the left side:

9S + 36S = 82.80

Add:

45S = 82.80

Divide both sides by 45"

S = 82.80 / 45

S = 1.84

One spoon cost $1.84


We know one knife cost 3 times as much, so multiply the cost of a spoon by 3:

Knife = 1.84 x 3 = $5.52

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Vanyuwa [196]

quelle est ta question?


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3 years ago
Carla says the value of the 4 in 365.24 has twice the value of the 2. Is she correct
kolezko [41]

Answer:

She is not correct


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