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3 years ago

Help me please I’ll give brainliest PLEASE HELP ASSP

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

6 0

Answer:

fundamental orders of connecticut

Step-by-step explanation:

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6x-y=3 this is the equation in standard form

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3 years ago

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If r=20.5 and s=34.2 find S Round to the nearest tenth

astraxan [27]

Answer: option d

Step-by-step explanation:

Remember the identity:

$tan\alpha=\frac{opposite}{adjacent}$

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "S":

$\alpha =arctan(\frac{opposite}{adjacent})$

Knowing that: you need to find the measure of the angle "S" , $r=20.5$ (which is the adjacent side) and $s=34.2$ (which is the opposite side), you can sustitute values into $\alpha =arctan(\frac{opposite}{adjacent})$

Then, you get that the measure of "S" rounded to the nearest tenth is:

$S=arctan(\frac{34.2}{20.5})\\\\S=59.1\°$

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4 years ago

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What is 1 3/4 - 5/6r =8/3

fenix001 [56]

1 3/4 - 5/6r = 8/3

-5/6r + 7/4 = 8/3

-5/6r +7/4 - 7/4 = 8/3 -7/4
-5/6r = 11/12

(6/-5)*(-5/6r)=(6/-5)*(11/12)
=-11/10

r = -1 1/10

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3 years ago

If you are picking a number between one and 20 what is the probability that you will pick a number greater than 14 or less than

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3 years ago

Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin4t,sin7t,9t⟩,r(0)=⟨9,8,3⟩

Makovka662 [10]

$\mathbf r'(t)=\langle\sin4t,\sin7t,9t\rangle$
$\implies\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt$
$\mathbf r(t)=\displaystyle\left\langle\int\sin4t\,\mathrm dt,\int\sin7t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle$
$\mathbf r(t)=\left\langle-\dfrac14\cos4t+C_1,-\dfrac17\cos7t+C_2,-\dfrac92t^2+C_3\right\rangle$

With $\mathbf r(0)=\langle9,8,3\rangle$ , we have

$\langle9,8,3\rangle=\left\langle-\dfrac14+C_1,-\dfrac17+C_2,C_3\right\rangle$
$\implies C_1=\dfrac{37}4,C_2=\dfrac{57}7,C_3=8$
$\implies\mathbf r(t)=\left\langle-\dfrac14\cos4t+\dfrac{37}4,-\dfrac17\cos7t+\dfrac{57}7,-\dfrac92t^2+8\right\rangle$

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4 years ago