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Kipish [7]
4 years ago
7

Mrs. Adams has 45 pencils. Mrs. Adams puts an equal share of pencils in each of five boxes. Mrs.Adams writes 45 ÷ 9 = 5 and 45 ÷

5 = 9 on the board. Mrs. Adams says that one division equation helps her find an equal share of pencils to put in each box and one division equation helps her prove her thinking is correct. Which division equation helps Mrs. Adams find an equal share to put in each box.
Mathematics
1 answer:
Hatshy [7]4 years ago
5 0
45÷5=9 is the equation that helps her find an equal share and 45÷9=5 is the equation that proves her thinking is correct
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The Gleason family has a monthly budget of $4,500. Mr. Gleason has a full-time job and takes home $900 each week. Mrs. Gleason w
lana [24]

Answer:

The value of x from the equation is 100. Thus, Mrs. Gleason should work for 100 hours per month. 

Step-by-step explanation:

To answer this item, we let x be the number of hours per month that Mrs. Gleason should work. The total budget is equal to sum of the amount acquired by Mr. Gleason and Mrs. Gleason. The equation that would express this is,

                         4,500 = 900(4) + 9x

The value of x from the equation is 100. Thus, Mrs. Gleason should work for 100 hours per month. 

I am sorry if you get this wrong.

4 0
4 years ago
A lamp has two bulbs, each of a type with average lifetime 1400 hours. Assuming that we can model the probability of failure of
liq [111]

Answer:

The probability of failure of both the bulbs  is 0.4323.

Step-by-step explanation:

For an exponential distribution the distribution is given by

f(x,\lambda )=\int_{0}^{x }\lambda e^{-\lambda x}dx

The value of λ is related to the mean μ as λ=1/μ,

Let us denote the 2 bulbs by X and Y thus the probability distribution of the 2 bulbs is as under

P(X)=\int_{0}^{x }\lambda _{X}e^{-\lambda _{X}x}dx

Similarly for the bulb Y the distribution function is given by

P(Y)=\int_{0}^{y }\lambda _{Y}e^{-\lambda _{Y}y}dy

Thus the probability for both the bulbs to fail within 1500 hours is

P(E)=\int_{0}^{1500}\int_{0}^{1500}\frac{1}{1400}e^{\frac{-x}{1400}}\cdot \frac{1}{1400}e^{\frac{-y}{1400}}dxdy\\\\P(E)=\frac{1}{1400^2}(\int_{0}^{1500}\int_{0}^{1500}e^{\frac{-x}{1400}}\cdot e^{\frac{-y}{1400}}dxdy)\\\\P(E)=\frac{1}{1400^2}(\int_{0}^{1500}e^{\frac{-x}{1400}}dx)\cdot (\int_{0}^{1500}e^{\frac{-y}{1400}}dy)\\\\P(E)=\frac{1}{1400^{2}}\times 920.473\times 920.473\\\\\therefore P(E)=0.4323

6 0
3 years ago
5x-8(3y+13)-1 what's the expression
Tanya [424]
Did u try looking it up?
3 0
3 years ago
Anybody can help me?
irinina [24]

Graph C depicts the relation between No. of sweaters ( Nombre de chandails vendus ) and the fund raised in the campaign (Campagne de financements )

<h3>What is a Graph ?</h3>

Graph is the statistical representation of data , It helps to observe large data systematically.

It is given that

Sale of one sweater gives $3

The relation between the amount raised for funding , M and the number of shirts sold , n is given by

M = 3n

It has to be found that which graph exactly depicts the relation and the condition as given

Graph C depicts the relation given as , The graph is between No. of sweaters ( Nombre de chandails vendus ) and the fund raised in the campaign (Campagne de financements ) , and for every 100 sweater , $300 is earned .

Therefore Graph C is the answer.

To know more about Graph

brainly.com/question/14375099

#SPJ1

6 0
2 years ago
I need help with math work!!
Akimi4 [234]

Answer:

(g-h)=x^2+5-8-x

=x^2-x-3

(g-h)(-9) means x= -9

x^2-x-3

=(-9)^2-(-9)-3

=81+9-3

=90-3

=87

4 0
3 years ago
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