Mrs. Adams has 45 pencils. Mrs. Adams puts an equal share of pencils in each of five boxes. Mrs.Adams writes 45 ÷ 9 = 5 and 45 ÷
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Answer:
a) 0.21% probability that there are no bad peaches in the peach cobbler.
b) 99.79% probability of having at least 1 bad peach in the peach cobbler
c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?
Desired outcomes:
12 good peaches, from a set of 12. So
Total outcomes:
12 peaches, from a set of 15. So
Probability:
0.21% probability that there are no bad peaches in the peach cobbler.
(b) What is the probability of having at least 1 bad peach in the peach cobbler?
Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So
p + 0.21 = 100
p = 99.79
99.79% probability of having at least 1 bad peach in the peach cobbler
(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?
Desired outcomes:
2 bad peaches, from a set of 3.
One good peach, from a set of 12.
Total outcomes:
12 peaches, from a set of 15. So
Probability:
7.91% probability of having exactly 2 bad peaches in the peach cobbler.
Answer:
10.6
Step-by-step explanation:
1. First, we need to find which digits √(113) is between, and that would be 10 and 11.
2. Okay, so √(113) is between 10 and 11, meaning 113 is between 100 and 121.
3. Since 113 is a little over half between 100 and 121, let's multiply 10.6 by 10.6 to see how close we are to 113:
4. 112.36 is pretty close to 113, therefore, the dot on the number-line should be placed at 10.6.