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dimulka [17.4K]
3 years ago
6

A plane flew for 5 hours heading west and for 4 hours heading south. If the total distance traveled was 3,444 miles, and the pla

ne traveled 39 miles per hour faster heading west, at what speed was the plane traveling west?
Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:400 miles per hour

Step-by-step explanation:

Let w = speed at which the plane travelled west

Let s = speed at which the plane travelled south

Distance moved in 5 hrs heading west = 5*w = 5w

Distance moved in 4 hrs heading south = 4*s = 4s

Total distance, 3444= 5w + 4s

w = s + 39( 39 miles/hr faster)

5(s+39) + 4s = 3444

5s + 195 + 4s = 3444

9s = 3249

s = 361 miles per hour

w = s + 39 = 361 +39

= 400 miles per hour

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nadezda [96]

Answer:

The rate is  1 ÷ 2 yards per hour

Step-by-step explanation:

The computation of the rate does the amount of yarn changes is given below:

= 3 3 ÷ 4 - 1 1 ÷8

= 15 ÷ 4 - 9 ÷ 8

= 21 ÷ 8 yards

 Now divide the above fraction by the number of hours

= 21 ÷ 8 yards ÷ 5 1 ÷ 4

= 21 ÷ 8 ×  4 ÷ 21

= 1 ÷ 2 yards per hour

Hence, the rate is  1 ÷ 2 yards per hour

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3 years ago
75 students in a kindergarten. 40% of them can read. how many can read?
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Answer:

30

Step-by-step explanation:

75 times .40 = 30

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3 years ago
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What is the solution of log base of (2x + 3) 125 = 3?
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strojnjashka [21]

Answer:

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Step-by-step explanation:

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3 years ago
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If bolt thread length is normally distributed, what is the probability that the thread length of a randomly selected bolt is Wit
KatRina [158]

Answer:

a) 0.5762

b) 0.0214

c) 0.2718

Step-by-step explanation:

It is given that lengths of the bolt thread are normally distributed. So in order to find the required probability we can use the concept of z distribution and z scores.

Part a) Probability that length is within 0.8 SDs of the mean

We have to calculate the probability that the length of a bolt thread is within 0.8 standard deviations of the mean. Recall that a z- score tells us that how many standard deviations away a value is from the mean. So, indirectly we are given the z-scores here.

Within 0.8 SDs of the mean, means from a score of -0.8  to +0.8. i.e. we have to calculate:

P(-0.8 < z < 0.8)

We can find these values from the z table.

P(-0.8 < z < 0.8) = P(z < 0.8) - P(z < -0.8)

= 0.7881 - 0.2119

= 0.5762

Thus, the probability that the thread length of a randomly selected bolt is within 0.8 SDs of its mean value is 0.5762

Part b) Probability that length is farther than 2.3 SDs from the mean

As mentioned in previous part, 2.3 SDs means a z-score of 2.3.

2.3 Standard Deviations farther from the mean, means the probability that z scores is lesser than - 2.3 or greater than 2.3

i.e. we have to calculate:

P(z < -2.3 or z > 2.3)

According to the symmetry rules of z-distribution:

P(z < -2.3 or z > 2.3) = 1 - P(-2.3 < z < 2.3)

We can calculate P(-2.3 < z < 2.3) from the z-table, which comes out to be 0.9786. So,

P(z < -2.3 or z > 2.3) = 1 - 0.9786

= 0.0214

Thus, the probability that a bolt length is 2.3 SDs farther from the mean is 0.0214

Part c) Probability that length is between 1 and 2 SDs from the mean value

Between 1 and 2 SDs from the mean value can occur both above the mean and below the mean.

For above the mean: between 1 and 2 SDs means between the z scores 1 and 2

For below the mean: between 1 and 2 SDs means between the z scores -2 and -1

i.e. we have to find:

P( 1 < z < 2) + P(-2 < z < -1)

According to the symmetry rules of z distribution:

P( 1 < z < 2) + P(-2 < z < -1) = 2P(1 < z < 2)

We can calculate P(1 < z < 2) from the z tables, which comes out to be: 0.1359

So,

P( 1 < z < 2) + P(-2 < z < -1) = 2 x 0.1359

= 0.2718

Thus, the probability that the bolt length is between 1 and 2 SDs from its mean value is 0.2718

4 0
3 years ago
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