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Makovka662 [10]
3 years ago
8

Solve each absolute value equation or inquality and choose the correct answer from the choices provided.

Mathematics
1 answer:
lawyer [7]3 years ago
7 0
1- 13 or -13 (B)

2- -5 < y < -3 (A)

3- t = 6 or -6 (B)

Hope this helps you =)
You might be interested in
Maya reads that 0.63 of Oak School is female and 0.47 of Elm School is female. She says that Oak School must have more females.
-BARSIC- [3]

Answer:

No not correct

Step-by-step explanation:

We are given information that Maya came to know that 0.63 pf Pal school is female and 0.47 of Elm school is female.

Without knowing the total number of students in each school, we cannot conclude that 0.63 is greater than 0.47

For example, say number of students in Oak school be 100, and in Elm school be 200

Females in Oak school = 0.63(100) =63

Females in Elm school = 0.47(200) = 94

We find that there are more females in Elm school

So with the information given, we cannot conclude she is correct , there are chances for her being wrong also.

4 0
3 years ago
Jessica's heart beats 12 times in 1/6 minute how many times does her heart beat each minute ​
Charra [1.4K]

Answer:

72

Step-by-step explanation:

12 6 times equals 72.

12x6=72

4 0
3 years ago
the cable of a hoist has a cross-section of 80 mm2. the hoist is used to lift a crate weighing 500 kg. what is the stress in the
Daniel [21]

Answer:

stress on the cable is 61.312mpa

If steel is used, extension will be 0.91968mm

If polypropylene is used, extension will be 0.1532mm

Step-by-step explanation: detailed explanation and calculation is shown in the image below

3 0
3 years ago
Find the slope and the y-intercept<br><br> 5x-3y=6
Alenkinab [10]

Answer: Look you have a website called symbolab and another called desmos for this stuff.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Based on historical data, your manager believes that 26% of the company's orders come from first-time customers. A random sample
scoundrel [369]

Answer:

\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})

And we can use the z score formula given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

And if we find the parameters we got:

\mu_p = 0.26

\sigma_p = \sqrt{\frac{0.26(1-0.26)}{158}} = 0.0349

And we can find the z score for the value of 0.4 and we got:

z = \frac{0.4-0.26}{0.0349}= 4.0119

And we can find this probability:

P(z>4.0119) = 1-P(z

And if we use the normal standard table or excel we got:

P(z>4.0119) = 1-P(z

Step-by-step explanation:

For this case we have the following info given:

p = 0.26 represent the proportion of the company's orders come from first-time customers

n=158 represent the sample size

And we want to find the following probability:

p(\hat p >0.4)

And we can use the normal approximation since we have the following two conditions:

1) np = 158*0.26 = 41.08>10

2) n(1-p) = 158*(1-0.26) = 116.92>10

And for this case the distribution for the sample proportion is given by:

\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})

And we can use the z score formula given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

And if we find the parameters we got:

\mu_p = 0.26

\sigma_p = \sqrt{\frac{0.26(1-0.26)}{158}} = 0.0349

And we can find the z score for the value of 0.4 and we got:

z = \frac{0.4-0.26}{0.0349}= 4.0119

And we can find this probability:

P(z>4.0119) = 1-P(z

And if we use the normal standard table or excel we got:

P(z>4.0119) = 1-P(z

8 0
3 years ago
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