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2 years ago

Solve each absolute value equation or inquality and choose the correct answer from the choices provided.

Mathematics

1 answer:

lawyer [7]2 years ago

7 0

1- 13 or -13 (B)

2- -5 < y < -3 (A)

3- t = 6 or -6 (B)

Hope this helps you =)

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I need help quick!!<br><br> you can have brainliest this is algerbra btw

padilas [110]

Answer:

Step-by-step explanation:

Day 1 = 2 birds

day 2 = 3 birds

day 3 = 9 birds

day 4 = 8 birds

day 5 = 1 bird

On day 1 the points are (1,2)

On day 5 the points are (5,1)

(I am picking these for the points because I don't know your options for the selecting area.)

we use this formula y2-y1/x2-x1

2-5/1-1

3/0

our answer is infinite which is the relation and this is an infinite function

5 0

2 years ago

Read 2 more answers

Who became president after the 1876 presidential election?<br> Nfnf

REY [17]

Answer:

Rutherford B. Hayes

Step-by-step explanation:

It was controversial, however Hayes was declared the winner of the election.

7 0

3 years ago

What is the product of 4 Over 5 times two-fifths?

Fudgin [204]

It’s 7 over 69 but 420 for a short answer

4 0

3 years ago

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There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=

yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = $\frac{12P4}{12^{4} }$

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = $\frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }$

P(X=2) = 0.401

P(X=3) = $\frac{4C3 * 12P2}{12^{4} }$

P(x=3) = 0.025

P(X=4) = $\frac{12}{12^{4} }$

P(X=4) = 0.001

Mean, $\mu = \sum xP(x)$

$\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879$

Standard deviation, $SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}$

SD = 1.033

4 0

3 years ago

Please help to find an explicit formula for calculating the sum Mn

defon

The explicit formula for calculating the sum is

$S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}$

The sum of the nth term of a sequence is expressed as;

$S_n=\frac{n}{2}(2a+(n-1)d)$

a is the first term

d is the common difference

n is the number of terms

For the sequence 0 + 1 + 2 + 3 +...

$S_n=\frac{n}{2}(2(0)+(n-1)1)\\S_n= \frac{n}{2}(n-1)\\S_n= \frac{n(n-1)}{2}$

Similarly for the sequence:

1 + 2+ 3 + 4+...

$S_n=\frac{n}{2}(2(1)+(n-1)1)\\S_n= \frac{n}{2}(2+n-1)\\S_n= \frac{n(n+1)}{2}$

Taking the product of the sum to get the explicit formula for calculating the sum

$S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}$

Learn more here: brainly.com/question/24547297

8 0

2 years ago