The answer please ok

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m. Based on past experience the company has determin

Gala2k [10]

Answer:

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.

We can consider 8 am = 0, and 8:30 am = 30, so $a = 0, b = 30$

Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

Between 15 and 25, so:

$P(15 \leq X \leq 25) = \frac{25 - 15}{30 - 0} = 0.3333$

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

8 0

3 years ago

In the supply-and-demand schedule shown above, the equilibrium price for portable music players is _____.

ad-work [718]

$150 because the supply number is equivalent to the demand number

6 0

3 years ago

Read 2 more answers

Does each equation represent exponential decay or exponential growth?

lisov135 [29]

Answer:

1. $H = 5.9(0.82)^{t}$ . Exponential decay function.

2. $y = 0.8(3.6)^{t}$ . Exponential growth function.

3. $f(t) = 0.72(15)^{t}$ . Exponential growth function.

4. $A = \frac{4}{9} (8)^{t}$ . Exponential growth function.

5. $A = (\frac{4}{3})^{t}$ . Exponential growth function.

6. $H = \frac{7}{2} (\frac{5}{6} )^{t}$ . Exponential decay function.

7. g(x) = 0.3(x). Not an exponential function.

Step-by-step explanation:

1. $H = 5.9(0.82)^{t}$ . This is an exponential decay function.

As the value of t increases H-value decreases.

2. $y = 0.8(3.6)^{t}$ . This is an exponential function of growth.

As the value of t increases y-value also increases.

3. $f(t) = 0.72(15)^{t}$ . This is an another example of exponential growth function.

As the value of t increases f(t)-value also increases.

4. $A = \frac{4}{9} (8)^{t}$ . This is again an example of exponential growth function.

As the value of t increases A-value also increases.

5. $A = (\frac{4}{3})^{t}$ . This is again an example of exponential growth function.

As the value of t increases A-value also increases.

6. $H = \frac{7}{2} (\frac{5}{6} )^{t}$ . This is another an example of exponential decay function.

As the value of t increases, H-value decreases.

7. g(x) = 0.3(x). This is a non-exponential function. (Answer)

4 0

4 years ago

Find an equation for the inverse for each of the following.

IgorLugansk [536]

Answer:

To solve these first swap x and y, solve for y and name it inverse function

3. y = -8x + 2

x = -8y + 2
8y = -x + 2
y = -x/8 + 2/8
y = -(18)x + 1/4

f⁻¹(x) = -(18)x + 1/4

-----------------------------------------

4. y = (2/3)x - 5

x = (2/3)y - 5
(2/3)y = x + 5
y = (3/2)x + (3/2)5
y = 1.5x + 7.5

f⁻¹(x) = 1.5x + 7.5

-----------------------------------------

5. f(x) = 2x² - 6

x = 2y² - 6
2y² = x + 6
y² = 1/2x + 3
y = $\sqrt{1/2x + 3}$

f⁻¹(x) = $\sqrt{1/2x + 3}$

-----------------------------------------

6. y = (x - 3)²

x = (y - 3)²
$\sqrt{x}$ = y - 3
y = 3 + $\sqrt{x}$

f⁻¹(x) = 3 + $\sqrt{x}$

4 0

3 years ago

The perimeter of a certain rectangle is 16 times the width. The length is 12 cm more than the width. Find the length and width o

Blizzard [7]

Check the picture below

surely you know how much that is.

8 0

3 years ago