The answer please ok

You mix 1 1/2 quarts of juice with 2 1/4 quarts of ginger L to make fruit punch what is the ratio of the amount of juice to the

Rudik [331]

3.75!!!!!!!!!!!!!!!!!!!!!!!!-

7 0

3 years ago

Item 12 You win an online auction for a toy. Your winning bid of $52 is 65% of your maximum bid. How much more were you willing

nataly862011 [7]

Answer:

$28

Step-by-step explanation:

Given that:

Value of Winning bid = $52

Winning bid 65% of the maximum bid.

To find:

How much more is the maximum bid from the winning bid ?

Solution:

We are given that the winning bid is 65% of the maximum bid.

Using this percentage value, we need to first find the value of maximum bid and then we need to subtract the value of winning bid from the maximum bid to find the answer.

Let the value of maximum bid = $ $x$

As per question statement:

$65%\ of\ x = 52\\\Rightarrow \dfrac{65}{100} \times x =52\\\Rightarrow 5x = 400\\\Rightarrow x = \dfrac{400}{5}\\\Rightarrow x =\$80$

Therefore, maximum bid = $80

Our answer is:

$80 - $52 = <em>$28</em>

5 0

3 years ago

A sequence starts 0,5 give a rule that sequence could follow and the next 3 terms for that rule

balu736 [363]

Answer:

hey did you ever found the answer because i need help with this question too

Step-by-step explanation:

3 0

4 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$