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lorasvet [3.4K]
3 years ago
10

Please help ILL MARK BRAINLIEST(17 points too)

Mathematics
1 answer:
jonny [76]3 years ago
3 0

Answer:

5, 10, 15, 20, 25, 30

6, 12, 18, 24, 30

Answer: 30

3, 6, 9, 12, 15, 18, 21, 24

24

Answer: 24

14, 28

4, 8, 12, 16, 20, 24, 28, 32

Answer: 28

Hoped it helped :)

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A cell phone bill provider offers a plan that costs $20 per month plus $0.10 per text message sent or received. A comparable pla
dybincka [34]

Answer:

100 texts

Step-by-step explanation:

20+.1x=30

30-20=10

10 dollar difference in base prices.

10/.1 (to find out how many texts)

100 texts

7 0
3 years ago
Which statement about the following equation is true?<br>2x2-9x+2-1​
Furkat [3]

Complete Question:

Which statement about the following equation is true?

2x^2-9x+2 = -1

A) The discriminant is less than 0, so there are two real roots

B) The discriminant is less than 0, so there are two complex roots

C) The discriminant is greater than 0, so there are two real roots

D) The discriminant is greater than 0, so there are two complex roots

Answer:

C) The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

The given equation is 2x^2-9x+2 = -1 which by simplification becomes

2x^2 - 9x + 3 = 0

For a quadratic equation of the form ax^2 + bx + c = 0, the discriminant is given by the equation, D = b^2 - 4ac

If the discriminant D is greater than 0, the roots are real and different

If the discriminant D is equal to 0, the roots are real and equal

If the discriminant D is less than 0, the roots are imaginary

For the quadratic equation under consideration, a = 2, b = -9, c = 3

Let us calculate the discriminant D

D = (-9)² - 4(2)(3)

D = 81 - 24

D = 57

Since the Discriminant D is greater than 0, the roots are real and different.

3 0
3 years ago
Help with 1 and 2 please
Anna35 [415]

Answer:

love your nails, can u bring it a bit closer tho?

Step-by-step explanation:

4 0
2 years ago
X to the power of two plus five x plus 4
Iteru [2.4K]

Answer: (x + 1) ( x + 4)

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml
irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.63}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.63}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

8 0
2 years ago
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