Answer is 10(2k+5)

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Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.

4 0

3 years ago

Which is the value of the expression ((10^4)(5^2)/(10^3)(5^3))^3

dimulka [17.4K]

Answer:

Step-by-step explanation:

Let's set this up to see if we can simplify it a bit:

$(\frac{10^4*5^2}{10^3*5^3})^3$

Notice we have 4 tens on top and 3 on bottom, so we can eliminate the bottom 3 altogether and leave just one on top. And we have 2 fives on the top and 3 on bottom, so we can eliminate the 2 on the top and leave one on the bottom. Now that looks like this:

$(\frac{10}{5})^3$

10 divided by 5 is 2, and 2 cubed is 8

8 0

3 years ago