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Dima020 [189]
3 years ago
15

Consider the functions f(x)=3x^2 - 5 and g(x)= √x -5 +2

Mathematics
2 answers:
lord [1]3 years ago
8 0

F(5):

f(5) = 3(5)^{2} - 5

f(5) = 15^{2} - 5

f(5) = 225 - 5

f(5) = 220


G(5):

g(5) = \sqrt{5} - 5 + 2

g(5) = 2,24 - 5 + 2

g(5) = -2,76 + 2

g(5) = -0,76


F(4):

f(4) = 3(4)^{2} - 5

f(4) = 12^{2} - 5

f(4) = 144 - 5

f(4) = 139


G(4):

g(4) = \sqrt{4} - 5 + 2

g(4) = 2 - 5 + 2

g(4) = -3 + 2

g(4) = -1



Hope it helped,


BioTeacher101

Eva8 [605]3 years ago
5 0

f(x) = 3x² - 5      

f(5) = 3(5)² - 5   →   f(5) = 3(25) - 5   →   f(5) = 75 - 5   →   f(5) = 70

f(4) = 3(4)² - 5   →   f(4) = 3(16) - 5   →   f(4) = 48 - 5   →   f(5) = 43

DOMAIN of f(x): All real numbers <em>(because there are no restrictions on "x")</em>

************************************************************

g(x) = \sqrt{x - 5} + 2

g(5) = \sqrt{5 - 5} + 2  →  g(5) =  \sqrt{0} + 2   →   g(5) = 2

g(4) = \sqrt{4 - 5} + 2   →  g(4) =  \sqrt{-1} + 2   →   g(4) = no real solutions

DOMAIN of g(x): x ≥ 5    <em>(because you cannot take the square root of a negative number)</em>


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