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liberstina [14]
3 years ago
13

Evaluate. 7^3 A) 21 B) 49 C) 81 D) 343

Mathematics
2 answers:
Mademuasel [1]3 years ago
5 0
The answer is a 73/3=21
ivolga24 [154]3 years ago
3 0
I think the answer is a
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Please help me solve this
Genrish500 [490]

Answer:

Solve what?

Step-by-step explanation:

You didn't put the question.

6 0
3 years ago
Clarissa has a budget of $1,200 a month to spend for rent and food. She has already spent $928 this month. Which inequality repr
Leviafan [203]
The answer is b. x(< with a line under it) 272
8 0
3 years ago
Read 2 more answers
The perimeter of this triangle is 25 units. An angle bisector divides one side of the triangle into lengths of 2 and 3. Find the
grin007 [14]

Answer:

   8 and 12

Step-by-step explanation:

Sides on one side of the angle bisector are proportional to those on the other side. In the attached figure, that means

  AC/AB = CD/BD = 2/3

The perimeter is the sum of the side lengths, so is ...

  25 = AB + BC + AC

  25 = AB + 5 + (2/3)AB . . . . . . substituting AC = 2/3·AB. BC = 2+3 = 5.

  20 = 5/3·AB

  12 = AB

  AC = 2/3·12 = 8

_____

<em>Alternate solution</em>

The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.

That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).

Likewise, 3 of the 15 units are in the segment being divided (BD), so the other 12 units are in that side of the triangle (AB).

The remaining sides of the triangle are AB=12 and AC=8.

7 0
3 years ago
Please answer this mathematical problem.
n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}

\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}

5 0
2 years ago
Solve using substitution.
alexandr1967 [171]
You take the first equation and make a value for y. So 6x + y =7 change it to :
y = -6x + 7
Now in the second equation replace the “y” with -6x +7 this is what it means to use substitution method . Your combined equation will now be :
8x + 9(-6x + 7) =17
Now do distributive property and you get :
8x + -54x +63 =17
Now combine like terms ;
-46x +63 =17
-46x =-46
x = 1
Now replace 1 for X value and we can get the value of Y .
Y=1
X=1
8 0
3 years ago
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