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forsale [732]
3 years ago
14

Are the triangles similar? If so, find x. Please help

Mathematics
1 answer:
dsp733 years ago
3 0

Answer:

there is one in the middile i hop it helps

Step-by-step explanation:

okay

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0.5 is ten times as great as?
GarryVolchara [31]
Let's cut the chit chat, and formalities. I'm not one for greetings or unnecessary niceties. 

Divide 0.5 by 10=
0.05

Check work.
0.05 x 10 = 0.5

3 0
3 years ago
Read 2 more answers
Your carry-on bag can weigh at most 40 pounds.Select an inequality that represents how much more weight x (in pounds) you can ad
andrey2020 [161]

Answer:

22 + x ≤ 40

x ≤ 18 pounds

Step-by-step explanation:

Maximum weight = 40 pounds

Initial weight = 22 pounds

Let Maximum weight that can be added = x

Mathematically, this means :

Initial weight + additional weight ≤ 40

That is ;

22 + x ≤ 40

Additional weight, x :

x ≤ 40 - 22

x ≤ 18 pounds

7 0
3 years ago
Segment wx is shown Explain how you would construct a perpendicular bisector of wx using a compass and a straightedge
n200080 [17]

Answer:

To perpendicular bisector of line segment WX. There are following steps:

1) Draw arcs or circles from points A and B on the both sides of WX.

2) Name the intersection points as W and X.

3) Use the straightedge to draw a line through points W and X.

4) Name the point as O

hence we have construct perpendicular bisector AB of WX which bisects at O.

4 0
3 years ago
At the craft store, Mark bought a bag of blue and brown marbles. The bag contained 20 marbles, and 30% of them were blue. How ma
kykrilka [37]

Answer:

6 blue marbles

Step-by-step explanation:

20 marbles * .30 are blue = blue marbles

20 * .30 = 6 blue marbles

5 0
3 years ago
Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal
a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

\dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{49}

Or, \dfrac{1}{y + 49} + \dfrac{1}{y} = \dfrac{1}{49}

Or, \dfrac{y + 49 + y}{y^{2} + 49 y } = \dfrac{1}{49}

Or, 2 y + 49 = \dfrac{y^{2}+49y }{19}

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = \frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or,  y = \frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}

Or, y = \frac{- 1 \pm \sqrt{121+3724}}{2}

or, y = \frac{- 1 \pm \sqrt{3845}}{2}

or, y = \frac{- 1 \pm 62.008}{2}

∴   y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0
3 years ago
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