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3 years ago

Please help me with this problem and if you can show your work

Mathematics

1 answer:

ella [17]3 years ago

7 0

Answer:

2.9

just answering wrong because i need points sorry

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Find the volume of the solid bounded by z = 2 - x2 - y2 and z = 1. Express your answer as a decimal rounded to the hundredths pl

butalik [34]

Answer:

The answer is " $(\frac{\pi}{2})$ ".

Step-by-step explanation:

$z = 2 - x^2 - y^2.........(1) \\\\z = 1.............(2)$

Let add equation 1 and 2:

Using formula: $x^2+y^2=1 \\\\$

convert to polar coordinates

$r=2$

$\theta \varepsilon (0=\pi)=z\\\\V=\int^{2\pi}_{\theta=0}\int^{1}_{\pi=0}\int^{z_{2}}_{z_1} r \ dr \d \theta\\\\$

$=\int^{2\pi}_{0}\int^{1}_{0} (Z_2-z_1)r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} 1- (-1-x^2-y^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (+1 \pm r^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (-r^3 + r) \ dr \d \theta\\\\=\int^{2\pi}_{0} (-\frac{r^4}{4}+\frac{r^2}{1})^{1}_{0} \d \theta\\\\=\int^{2\pi}_{0} (\frac{1}{4}) \d \theta\\\\=(\frac{2 \pi}{4}) \\\\=(\frac{\pi}{2}) \\\\$

8 0

3 years ago

(-327) + 420 + 521=

Tems11 [23]

144 hope this helps! :)

6 0

3 years ago

Read 2 more answers

Round off 24.67 to one significant

marishachu [46]

24.67 rounded to one significant figure would be 25.

4 0

3 years ago

Read 2 more answers

Ben was walking in Manhattan at a constant speed. He went along 5th avenue from 4th to 98th street. At 3:00 he was on 15th stree

muminat

Answer: The starting time is 2:27 and finishing time is 7:09.

Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.

Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.

That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes, so the time taken to cover 1 street is 3 minutes.

Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.

And his finishing time was (4:30 + 3×53 min) = 7:09.

Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as

$N=4+\dfrac{T}{3.}$

Thus, the starting and finishing time was 2:27 and 7:09 respectively.

3 0

3 years ago

students who failed mathematics scored the following marks 16.5,13.6,12.4,13.7 find the average mark for this students

SSSSS [86.1K]

Answer:

16.5+13.6+12.4.17.7= 60.2

60.2÷4 =15.05

8 0

3 years ago

Please help me with this problem and if you can show your work​

Please help me with this problem and if you can show your work