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3 years ago

13

Suppose you got 3 out every 4 questions correct on your homework. How many total questions were on the homework if you got 12 qu

estions correct?

1 answer:

Andrej [43]3 years ago

5 0

Answer:

9

Step-by-step explanation:

there's 12 questions

divided 12 by 4 because its every for questions

3 parts every third question is wrong

so 3 wrong = 9

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Please Help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Oduvanchick [21]

Answer:

26:26

Step-by-step explanation:

I hope I've helped :)

4 0

3 years ago

Goods are purchased for ₹1500. If one fifth of the goods sold at a profit of 5% and the remaining four-fifth of the goods at a p

Tpy6a [65]

Answer:

9%

Step-by-step explanation:

Cost of 1/5 good = 1500*1/5= 300

Profit= 5%

SP = (profit+100)/100*CP

SP= (5+100)/100*300

SP = 105/100*300

SP= 1.05*300= 315

Cost of 4/5 good = 1500*4/5= 1200

Profit= 10%

SP= (profit+100)/100*CP

SP= (10+100)/100*1200

SP = 110/100*1200

SP= 1.10*1200= 1320

Total SP = 315+1320= 1635

Net profit= 1635-1500= 135

Profit% = 135/1500*100%

Profit% = 0.09*100%

Profit% = 9%

6 0

3 years ago

Read 2 more answers

Diego's bank granted him

DanielleElmas [232]

Answer:

$72500

Step-by-step explanation:

$72500

5 0

2 years ago

Nethan made 8 rose bouquets and 6 daffodil bouquets. Nethan only has enough flowers to make at most 20 rose or daffodil bouquets

Solnce55 [7]

Answer:

Nethan made 8 rose bouquets and 6 daffodil bouquets.

Nethan only has enough flowers to make at most 20 rose or daffodil bouquets total.

Let x represents the number of more rose bouquets.

Let y represents the number of more daffodil bouquets.

The maximum bouquets that can be made = 20

And the number of bouquets made are = 14

So, additional bouquets are = $20-14=6$

In equation form we can show like :

$x +y= 6$

or $y=6 -x$

or $x=6- y$

Putting values of x as 0,2,4 and 6 we get:

When x = 0 then y = 6

When x = 2 then y = 4

When x = 4 then y = 2

When x = 6 then y = 0

You can see the graph attached.

3 0

3 years ago

The lengths, in minutes, of the movies currently showing at a movie theater are shown in the data set. Create a histogram

alexdok [17]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required lengths are not given.

I will use the following data set to answer the question.

$Dataset: 35, 51, 39, 42, 68, 62, 32, 59$

First, is to determine the range of the dataset

$Range = Highest - Least$

$Range = 68 - 32$

$Range = 36$

Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval

$Class= Range/10$

$Class = 36/10$

$Class = 3.6$

$Class \approx 4$

<em>So, we use 4 classes</em>

Plot the frequency distribution table as follows:

$\begin{array}{ccc}{Intervals} & {Observations} & {Frequency} & {31-40} & {32,35,39} & {3} & {41-50} & {42} & {1} & {51-60} & {51,59} & {2} & {61-70} & {62,68} & {2}\ \end{array}$

<em>See attachment for histogram</em>

5 0

3 years ago