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maks197457 [2]
3 years ago
10

How many square feet of outdoor carpet will we need for this hole?

Mathematics
1 answer:
finlep [7]3 years ago
8 0

Answer:38sqft

Step-by-step explanation:the rectangle portion is 24sqft, the top triangle portion is 6sqft and the bottom triangle is 8 sqft

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PLEASE HELP I WILL GIVE 100 POINTS!!!!!!!!Given rectangle ABCD ~ HGFE , what is the length of HG ?
never [62]
Since rectangle ABCD is similar to  HGFE, the ratios of the lengths of their corresponding sides are equal. We can infer form our picture that AD is corresponding to EH and DC is corresponding to HG, so lets find the ratios of those corresponding sides and establish a proportion to find the length of HG:
\frac{AD}{EH} = \frac{DC}{HG}
We know that AD=45, EH=27, and DC=15, so lets replace those values in our proportion:
\frac{45}{27} = \frac{15}{HG}
HG= \frac{27*15}{45}
HG= \frac{405}{45}
HG=9

We can conclude that the length of the segment HG is 9.

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3 years ago
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3 years ago
Jacob throws an acorn into the air. It lands in front of him. The acorn's path is
Burka [1]

Answer:

  • hits the ground at x = -0.732, and x = 2.732
  • only the positive solution is reasonable

Step-by-step explanation:

The acorn will hit the ground where the value of x is such that y=0. We can find these values of x by solving the quadratic using any of several means.

__

<h3>graphing</h3>

The attachment shows a graphing calculator solution to the equation

  -3x^2 + 6x + 6 = 0

The values of x are -0.732 and 2.732. The negative value is the point where the acorn would have originated from if its parabolic path were extrapolated backward in time. Only the positive horizontal distance is a reasonable solution.

__

<h3>completing the square</h3>

We can also solve the equation algebraically. One of the simplest methods is "completing the square."

  -3x^2 +6x +6 = 0

  x^2 -2x = 2 . . . . . . . . divide by -3 and add 2

  x^2 -2x +1 = 2 +1 . . . . add 1 to complete the square

  (x -1)^2 = 3 . . . . . . . . written as a square

  x -1 = ±√3  . . . . . . . take the square root

  x = 1 ±√3 . . . . . . . add 1; where the acorn hits the ground

The numerical values of these solutions are approximately ...

  x ≈ {-0.732, 2.732}

The solutions to the equation say the acorn hits the ground at a distance of -0.732 behind Jacob, and at a distance of 2.732 in front of Jacob. The "behind" distance represents and extrapolation of the acorn's path backward in time before Jacob threw it. Only the positive solution is reasonable.

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1 year ago
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Answer:

Step-by-step explanation:

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Answer:

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