Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Answer: 7
Step-by-step explanation: I had this question before
An = a1 r^(n-1)
here a1 = 6 and r = 3 so
a7 = 6 * 3^(7-1)
= 4374 answe
Answer:
AC=14
X=10
Y=1
Hoped this helped!
Step-by-step explanation:
DE is half of BC, therefore x=10. AE and EC have to be the same length, which is 7. SO, y=1 and x is 10.
In parallelogram LMNO, NO = 10.2, and LO = 14.7. The basic property of a parallelogram that the opposite sides in a parallelogram are equal; so, two sides are 10.2 (NO=LM=10.2), and two sizes are 14.7, = (LO=MN=14.7).
The perimeter of the parallelogram LMNO is:
P= 2NO + 2LO.
P= (2 x 10.2)+(2 x 14.7).
P= 20.4 + 29.4.
So, P= 49.8.
