In some cases, finding the limit lets you find numbers simple solutions would't allow you to find. For example, with the equation (limit being x approaching 0), if you have the equation (x^2+1)/x, you can't plug 0 into the equation because you'd be dividing by 0. Finding the limit allows you to see the number approaching 0 even though you can't actually plug 0 into the equation.
W = L - 7
WL = 78
(L-7)L = 78
L^2 - 7L - 78 = 0
Factorize: (L-13)(L+6) = 0
L = 13 or -6
A length cannot be negative, so the length must be 13 miles.
The width is 13-7 = 6 miles.
Multiply the fraction by 100%.
![\dfrac{45}{75}\times 100\%=60\%](https://tex.z-dn.net/?f=%5Cdfrac%7B45%7D%7B75%7D%5Ctimes%20100%5C%25%3D60%5C%25)
The answer to this question is c
Answer:
D) 8, 40, 41
Step-by-step explanation:
![{8}^{2} + {40}^{2} = 64 + 1600 = 1664...(1) \\ {41}^{2} = 1681...(2) \\ from \: (1) \: and \: (2) \\ {8}^{2} + {40}^{2} \neq \: {41}^{2} \\](https://tex.z-dn.net/?f=%20%7B8%7D%5E%7B2%7D%20%20%2B%20%20%7B40%7D%5E%7B2%7D%20%20%3D%2064%20%2B%201600%20%3D%201664...%281%29%20%5C%5C%20%20%7B41%7D%5E%7B2%7D%20%20%3D%201681...%282%29%20%5C%5C%20from%20%5C%3A%20%281%29%20%5C%3A%20and%20%5C%3A%20%282%29%20%5C%5C%20%20%7B8%7D%5E%7B2%7D%20%20%2B%20%20%7B40%7D%5E%7B2%7D%20%20%5Cneq%20%5C%3A%20%20%7B41%7D%5E%7B2%7D%20%20%5C%5C%20)