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2 years ago

Can someone be kind enough and help me I've posted my question many times and no one has answered

Mathematics

1 answer:

ahrayia [7]2 years ago

3 0

Answer:

The symbol that should be used is >

Step-by-step explanation:

In the question it says that half of a number is greater than 1 1/3 of a number, which only leaves that as an option

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65.4 x 2.3 SHOW WORK!!! plz

bagirrra123 [75]

Answer:

Hello so.

65.4 x 2.3 = 150.42

Step-by-step explanation:

The Images I have attached show the work.

6 0

3 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

3 years ago

Question 2 options:

Alex777 [14]

7736.4uhshshszszehzeehe

3 0

3 years ago

Would you measure the length of a jump rope in inches or in feet? explain your choice

yan [13]

Depending on the length of the jump rope but usually you may need both feet and inches. By checking the average lengths of a jump rope you have: 7ft, 8ft,9ft,10ft for different heights so from this information the correct answer is feet

5 0

3 years ago

Read 2 more answers

When using the quadratic formula, can you predict when the solutions will be real versus imaginary? Explain.

jok3333 [9.3K]

If the part inside the square root is negative, there are imaginary roots. Otherwise they are real.

4 0

3 years ago

Can someone be kind enough and help me I've posted my question many times and no one has answered​

Can someone be kind enough and help me I've posted my question many times and no one has answered