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3 years ago

Find the values of the variables in this kite.

Mathematics

1 answer:

zavuch27 [327]3 years ago

4 0

Answer:

x=7, y=16

Step-by-step explanation:

2x+5=x+12

2x=x+7

x=7

y-4=x+5

y-4=12

y=16

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imagine you live only one mile from work and you decide to walk. if you walk four miles per hour, how long will it take you to w

fiasKO [112]

Answer:the distance to work is 1 mile and you can walk at 4 miles per hour, then you can walk 1 mile in ¼ hr = 15 minutes

Step-by-step explanation:

Dylan,

If the distance to work is 1 mile and you can walk at 4 miles per hour, then you can walk 1 mile in ¼ hr = 15 minutes.

To set up the "equation" think about it this way: (1 mile/ t) = (4 mile/ 1 hr)

so 1/t = 4/1 hr

now multiply both sides by t to get 1 = t·(4/1 hr), next divide both sides by (4/1 hr)

t = 1/(4/ 1 hr) = 1 hr/4 = ¼ hr = 15 min.

8 0

3 years ago

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I need these answers by 1:30

hodyreva [135]

Answer:

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Step-by-step explanation:

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2 years ago

A rectangle has a height of 4w^3 and a width of 5w^2-3w-4.

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Area of the entire rectangle = height * width

= 4w³ *( 5w²-3w-4)

= 4w³ * 5w²- 4w³ *3w - 4w³ *4

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6 0

2 years ago

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I don't get this can somone help me please

wolverine [178]

Answer:

f = m+h

Step-by-step explanation:

just add h to both sides of the equation to isolate f.

Hope this helps!

7 0

2 years ago

A rare form of malignant tumor occurs in 11 children in a million, so its probability is 0.000011. Four cases of this tumor occ

Shkiper50 [21]

Answer:

a) The mean number of cases is 0.14608 cases.

b) The probability that the number of cases is exactly 0 or 1 is 0.990.

c) The probability of more than one case is 0.010

d) No, because the probability of more than one case is very small

Step-by-step explanation:

We can model this problem with a Poisson distribution, with parameter:

$\lambda=r*t=0.000011*13,280=0.14608$

a) The mean amount of cases is equal to the parameter λ=0.14608.

b) The probability of having 0 or 1 cases is:

$P(k=0)=\frac{\lambda^0 e^{-\lambda}}{0!}=\frac{1*0.864}{1} =0.864\\\\ P(k=1)=\frac{\lambda^1 e^{-\lambda}}{0!}=\frac{0.14608*0.864}{1} =0.126\\\\P(k\leq1)=0.864+0.126=0.990$

c) The probability of more than one case is:

$P(k>1)=1-P(k\leq 1)=1-0.990=0.010$

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.

7 0

2 years ago