Answer:
Because the kind of compounfds that you try to determine using paper chromatography (organic compounds) are usually not soluble in water. Furthermore, water could react chemically with some of this compounds, because it's a very reactive molecule. You need organic solvents that are mostly inert.
Answer:
4.0506100 x 10^-1
Step-by-step explanation:
Because all you need to do is move the decimal point to the right once, you write 10^-1 to show that to get back to the original number, you just multiply 4.0506100 by -0.1
Answer:
the 2nd one (60m minutes)
Step-by-step explanation:
60 minutes in an hour, so if m is the number of hours you would times that by the number of minutes in an hour which is sixty. 60m is 60 times m
You will save $172.65 if you buy an item listed as 575.60
From the box plot, it can be seen that for grade 7 students,
The least value is 72 and the highest value is 91. The lower and the upper quartiles are 78 and 88 respectively while the median is 84.
Thus, interquatile range of <span>the resting pulse rate of grade 7 students is upper quatile - lower quartle = 88 - 78 = 10
</span>Similarly, from the box plot, it can be seen that for grade 8 students,
The
least value is 76 and the highest value is 97. The lower and the upper
quartiles are 85 and 94 respectively while the median is 89.
Thus, interquatile range of the resting pulse rate of grade 8 students is upper quatile - lower quartle = 94 - 85 = 9
The difference of the medians <span>of the resting pulse rate of grade 7 students and grade 8 students is 89 - 84 = 5
Therefore, t</span><span>he difference of the medians is about half of the interquartile range of either data set.</span>
