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ehidna [41]
4 years ago
6

What will the following program display?

Computers and Technology
1 answer:
s344n2d4d5 [400]4 years ago
5 0

Answer:

0 1 1 0

Explanation:

Running the below code

#include <iostream>

using namespace std;

int main() {

   int a = 0, b = 2, x = 4, y = 0;

   cout << (a == b) << " ";

   cout << (a != b) << " ";

  cout << (b <=x) << " ";

  cout << (y > a) << endl;

   return 0;

}

line 5 = states is a == b, i.e 0 == 2, which returns false 0

line 6 = states is a != b i.e 0 not equal to 2 returns true 1

line 7 = states is b <= x i.e 2 less than or equal to 4 returns true 1

line 8 = states is y >a i.e 0 > 0 returns false 0

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Hi everyone can anyone tell me how to align the photo the right in code.org
Ostrovityanka [42]

Answer:

Step 1: Wrap the image in a div element. Step 2: Set the display property to "flex," which tells the browser that the div is the parent container and the image is a flex item. Step 3: Set the justify-content property to "right." Step 4: Set the width of the image to a fixed length value

Explanation:

6 0
3 years ago
Create a SavingsAccount class. Use a static data member annualInterestRate to store the annual interest rate for each of the sav
andrew-mc [135]

Answer:

see explaination

Explanation:

SavingsAccount.h

#pragma once

#ifndef SAVINGS_H

#define SAVINGS_H

//SavingsAccount class declaration

class SavingsAccount

{

//declare data members

private:

//set annualInterestRate to 0.0 default value

static double annualInterestRate;

double savingsBalance;

public:

//set the balance

void setBalance(double);

//modify interest rates

static void modifyInterestRate(double);

//retruns total balance with interest

double calculateMonthInt();

};

#endif

SavingsAccount.cpp

//include required header files

#include<iostream>

#include"SavingsAccount.h"

using namespace std;

//set the annualInterestRate to 0

double SavingsAccount::annualInterestRate = 0;

//static funtion modify interest rate

void SavingsAccount::modifyInterestRate(double iRate)

{

annualInterestRate = iRate;

}

//set the balance

void SavingsAccount::setBalance(double bal)

{

savingsBalance = bal;

}

//calculating savings balance with monthly interest

double SavingsAccount::calculateMonthInt()

{

double monthInt = 0;

monthInt += savingsBalance*annualInterestRate / 12;

return savingsBalance += monthInt;

}

DriverProgram.cpp

//include required header files

#include<iostream>

#include "SavingsAccount.h"

using namespace std;

//main methods

int main()

{

//delcare class objects

SavingsAccount saver1, saver2;

//setter functions of balance

saver1.setBalance(2000.00);

saver2.setBalance(3000.00);

//Setting annual interset 0.03 to static variable

saver1.modifyInterestRate(0.03);

//finding the balance in saver1 and saver2 account

cout << "Balance of saver1 and saver2 on 3% interest Rate\n";

cout << "--------------------------------------------------\n";

cout << "Balance of saver1 = " << saver1.calculateMonthInt()

<< endl;

cout << "Balance of saver2 = " << saver2.calculateMonthInt()

<< endl << endl;

//Setting annual interset 0.04 to static variable

saver1.modifyInterestRate(0.04);

cout << "Balance of saver1 and saver2 on 4% interest Rate\n";

cout << "---------------------------------------------------\n";

cout << "New Balance of saver1 = " << saver1.calculateMonthInt() << endl;

cout << "New Balance of saver2 = " << saver2.calculateMonthInt() << endl<<endl;

return 0;

}

4 0
3 years ago
.in the array based list implementation of the ADT what is the worst case time efficiency of the getEntry method?
kenny6666 [7]

Answer:

c.O(n)

Explanation:

In the array based list implementation of the ADT the worst case time complexity of the getEntry method is O(n).In the worst case it has to travel upto n elements then it has to do the operation.In doing so  the time complexity will come out to be O(n).So we conclude that the answer to this question is O(n).

5 0
4 years ago
Create a program to calculate the wage. Assume people are paid double time for hours over 60 a week. Therefore they get paid for
Rus_ich [418]

Answer:

Written in Python

name = input("Name: ")

wageHours = int(input("Hours: "))

regPay = float(input("Wages: "))

if wageHours >= 60:

->total = (wageHours - 60) * 2 * regPay + 20 * 1.5 * regPay + regPay * 40

else:

->total = wageHours * regPay

print(name)

print(wageHours)

print(regPay)

print(total)

Explanation:

The program is self-explanatory.

However,

On line 4, the program checks if wageHours is greater than 60.

If yes, the corresponding wage is calculated.

On line 6, if workHours is not up to 60, the total wages is calculated by multiplying workHours by regPay, since there's no provision for how to calculate total wages for hours less than 60

The required details is printed afterwards

Note that -> represents indentation

4 0
3 years ago
This is your chance to become the instructor. After learning the looping and input validation concepts, create a problem to give
enot [183]

Answer:

See Explaination

Explanation:

The Problem information is as follows:

The input: A data file containing the bank account information.Accounts are of different

types (like Savings Account, Checking Accounts).

The Output: Report on Number of Savings Account, Number of Checking accounts and their

total balances, avregae balance, maximum and minimum balance etc

Processing:

Read the file data

Consider valid account data

Separate different accounts

Calculate the sum of their balances

Calculate the average balnace for each type of account

Display the information

Solution:

1.The application should be able to read the csv file.

2.All the error checking should be done as per defined rules

3.The report should be generated in the defined format

4.Data display precisions need to be followed.

5.Interactive errors should be reported with proper messages

6.Integrity of the data should be maintaied while saving the data.

7. Calculation of the averageAccountBalance = (Sum of all the balances of a particular type of account)/(number of that type of account)

8. TotalAccountBalance = Sum of all the balances of each type of account.

9. To find maximum start with a default value and then traverse all the accounts and update the maximum value as per the comparison results

and same for minimum.

Input Validation:

1.Check for the filename (maximum length is 10 chars besides the csv extension)

2.account number (12 digits, first three entries are alphabets)

3.Name (Only alphabets are allowed)

4.Phone Number (7 digits must follow the format xxx-xxx-x)

pesudoCode:

Input filename

open the file

declare accounts[] array

Read the data in accounts and update numOfAccounts

declare numOfAccounts, numOfSavingActs, numOfCheckingActs, totalBalanceSavings, totalBalanceChecking, averageBalanceChecking

averageBalanceSavings, maximumSaavings, minimumSavings, maximumChecking, minimumChecking

for i = 1 to n:

if (Validate(account[i])):

if account[i].type == "Savings":

numOfSavingActs++

totalBalanceSavings = totalBalanceSavings + account[i].balance

if account[i].balance > maximumSavings:

maximumSavings = account[i].balance

if account[i].balance < minimumSavings:

minimumSavings = account[i].balance

if account[i].type == "Checkings":

numOfSavingActs++

totalBalanceSavings = totalBalanceSavings + account[i].balance

if account[i].balance > maximumSavings:

maximumSavings = account[i].balance

if account[i].balance < minimumSavings:

minimumSavings = account[i].balance

Display(Data)

4 0
3 years ago
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