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Akimi4 [234]
3 years ago
8

Raj gets a 1.5 mile head start and runs at a rate of 4.5 miles per hour. Jacinda's progress is represented by a graph that goes

through the points (1,10), (2,20), and (3,30). How long will Jacinda need to run to catch up with Raj?
Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
From the given ordered pair representing Jacinda's progress, her speed is equal to 10 miles per hour. Letting x be the time it takes for Jacinda to catch up with Raj, the total distance Raj would travel is 
                            1.5 + 4.5x
and Jacinda's total distance is 10x. Mathematically,
                                1.5 + 4.5x = 10x 
The value of x from the equation is 0.27 hours. Therefore, Jacinda needs to run 2.7 miles to catch up with Raj. 
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Zinaida [17]

Answer:

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4 0
3 years ago
A geometric sequence has u4= -70 and u7=8.75<br> Find the second term of the sequence.
Kobotan [32]

Answer:

-122.5

Step-by-step explanation:

Difference = 7 - 4 = 3 terms; 8.75 - (-70) = 78.75

1 term → 78.75/3 = 26.25

therefore, u2 = - 70 - 2(26.25) = -122.5

Topic: Patterns + Common difference

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5 0
3 years ago
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777dan777 [17]
I think it is 5 11/24
5 0
3 years ago
Read 2 more answers
Then determine which answer
shtirl [24]

Answer:

B.

Step-by-step explanation:

The graph that is going to show the function, has two parts: one for numbers equal or less than 3 and the other for numbers greater than 3

Then, for x≤3, the function is f(x) = 4. This is a constant so the graph is a horizontal line.

Additionally, for x>3, the function is f(x)=12x. This is a straight line with a positive slope.

So, the answer that follows these 2 conditions is B.

3 0
3 years ago
The path of a roller coaster over a particular length of track can be represented by a quadratic function f, where f(x) represen
alexgriva [62]
The roller coaster could be represented by the function for Choice D.

If you were to graph this function, you would find that the zeros (x-intercepts) of the function are at the points of -2 and 1. Those are the needed points in the problem.

Since this is a parabola that opens upward, the parabola must be below the axis (or support bar) between those values.
8 0
3 years ago
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