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Akimi4 [234]
3 years ago
8

Raj gets a 1.5 mile head start and runs at a rate of 4.5 miles per hour. Jacinda's progress is represented by a graph that goes

through the points (1,10), (2,20), and (3,30). How long will Jacinda need to run to catch up with Raj?
Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
From the given ordered pair representing Jacinda's progress, her speed is equal to 10 miles per hour. Letting x be the time it takes for Jacinda to catch up with Raj, the total distance Raj would travel is 
                            1.5 + 4.5x
and Jacinda's total distance is 10x. Mathematically,
                                1.5 + 4.5x = 10x 
The value of x from the equation is 0.27 hours. Therefore, Jacinda needs to run 2.7 miles to catch up with Raj. 
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3 times a number xx, subtracted from 1818, is less than -90.?90. Write an inequality for the statement above. Find the solution
Evgen [1.6K]

Answer:

The solution set is: x>36

Step-by-step explanation:

We are given that we have to subtract 3 times of some number 'x' from 18 such that the resulting equation is less than -90.

this means that : 18-3x<-90

on solving the inequality by adding 3x on both side and adding 90 on both side we get that

 108<3x

now on dividing both side by 3 we get that

x>36

Hence our solution set is: x>36


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Suppose that the height above ground of a person sitting on a Ferris wheel is described by the following.
sdas [7]

Answer:

Person will be 24 metres above the ground after 1.50 minutes

Step-by-step explanation:

Given:

h(t)=18.8-16.7\cos \left ( \frac{2\pi t}{5} \right )

To find:

time when the person be 24 meters above the ground

Solution:

Put h(t)=24

h(t)=18.8-16.7\cos \left ( \frac{2\pi t}{5} \right )\\24=18.8-16.7\cos \left ( \frac{2\pi t}{5} \right )\\16.7\cos \left ( \frac{2\pi t}{5} \right )=18.8-24\\16.7\cos \left ( \frac{2\pi t}{5} \right )=-5.2\\\cos \left ( \frac{2\pi t}{5} \right )=\frac{-5.2}{16.7}\\\cos \left ( \frac{2\pi t}{5} \right )=-0.3114\\\frac{2\pi t}{5}=1.887\\\frac{2}{5}\times \frac{22}{7}t=1.887\\t=1.887\times \frac{5}{2}\times \frac{7}{22}\\=1.501\\\approx 1.50 \,\,minute

So, the person will be 24 metres above the ground after 1.50 minutes

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3 years ago
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