Which coordinate pair is the best estimate of the point of intersection in this graph?
1 answer:
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Answer:
x=8
NR=5 units
BI=10 units
Step-by-step explanation:
In a rectangle BRIA
AN=5 units
NR=x-3
We have to solve for x , NR and BI.
We know that
Diagonals of rectangle bisect to each other.
BI and AR are the diagonals of rectangle BRIA and intersect at point N.
AN=NR
Substitute the value of x
NR=8-3=5
By property of rectangle
BI=AR=AN+NR=5+5=10 unit
BI=10 units
Answer:
The quotient will be
Step-by-step explanation:
We have given the equation
We have to find the quotient
From algebraic equation we know that
So
So the quotient will be
Hey there Fish Girl!
So, if![\left[\begin{array}{ccc}1/4 \end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F4%20%5Cend%7Barray%7D%5Cright%5D%20%20%20)
equals 50 miles, then we would do this multiplied by . . . .
So, if we would want to go to 3 whole, we would then have to go to the number 3 of course. So then, we do![\left[\begin{array}{ccc}4*3=12\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%2A3%3D12%5Cend%7Barray%7D%5Cright%5D%20%20%20)
and then from this, we would have to multiply this my 50.
The reason to why we would have to do this is because 1/4 of a mile is 50, so then, sense we are trying to get to the number 3, then, from doing this,we would determine a figure out how many miles this would conclude to be.
![\left[\begin{array}{ccc}12*50\end{array}\right] =\left[\begin{array}{ccc}\boxed{\boxed{600}} \ so \ far!\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%2A50%5Cend%7Barray%7D%5Cright%5D%20%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B600%7D%7D%20%5C%20so%20%5C%20far%21%5Cend%7Barray%7D%5Cright%5D%20)
So, now, we have covered 3 as a whole, then we would have to see how 3/8 and also 1/4 can relate to each other.
So, in this case,
So, most likely, it would stay the same as it is, 1/4 because this is almost half to.
SO ALL WE WOULD NEED TO DO NOW IS TO ADD . . . . .
![\left[\begin{array}{ccc}\left[\begin{array}{ccc}\boxed{\boxed{600+50 \ or \frac{1}{4}=650}} \end{array}\right]\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B600%2B50%20%5C%20or%20%20%5Cfrac%7B1%7D%7B4%7D%3D650%7D%7D%20%5Cend%7Barray%7D%5Cright%5D%5Cend%7Barray%7D%5Cright%5D%20%20%20)
YOUR CORRECT AND FINAL ANSWER TO THIS QUESTION WOULD BE. . . .
![\left[\begin{array}{ccc}650 \ miles\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D650%20%5C%20miles%5Cend%7Barray%7D%5Cright%5D%20%20%20)
Hope this helps you fish Girl! :)
So, if
So, if we would want to go to 3 whole, we would then have to go to the number 3 of course. So then, we do
The reason to why we would have to do this is because 1/4 of a mile is 50, so then, sense we are trying to get to the number 3, then, from doing this,we would determine a figure out how many miles this would conclude to be.
So, now, we have covered 3 as a whole, then we would have to see how 3/8 and also 1/4 can relate to each other.
So, in this case,
So, most likely, it would stay the same as it is, 1/4 because this is almost half to.
SO ALL WE WOULD NEED TO DO NOW IS TO ADD . . . . .
YOUR CORRECT AND FINAL ANSWER TO THIS QUESTION WOULD BE. . . .
Hope this helps you fish Girl! :)