If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
Yw and pls mark me brainiest
Answer:
Cost of adult ticket = $12.5
Cost of child ticket = $7.5
Step-by-step explanation:
Given:
Cost of 6 adult ticket and 5 child ticket = $112.5
Cost of 8 adult ticket and 4 child ticket = $130
Find:
Equation and solution
Computation:
Assume;
Cost of adult ticket = a
Cost of child ticket = b
So,
6a + 5b = 112.5....eq1
8a + 4b = 130 ......eq2
Eq2 x 1.25
10a + 5b = 162.5 .....eq3
eq3 - eq1
4a = 50
Cost of adult ticket = $12.5
8a + 4b = 130
8(12.5) + 4b = 130
Cost of child ticket = $7.5
Answer:
m= -13
Step-by-step explanation:
step1: left part times 26 is m
step2: right part times 26 is -13
so m= -13
Answer:1,750,000,000
Step-by-step explanation:first the number ten to the fifth power is 1,000,000 then times five is 5,000,000. Then the number ten to the negative fifth power is 50 times seven is 350. 5,000,000 times 350 is 1,750,000,000
Answer:
t=1/30 h = 2 min
Step-by-step explanation:
d = vt
system of equations:
d = 13t
d - 2/5 = t -> d = t+2/5
Solve
13t = t +2/5
t = 1/30 h = 60 min / 30 = 2 min