Answer:
m∠CEB is 55°
Step-by-step explanation:
Since ∠ADE = 55°, and ∠ADE is half of ∠ADC because ED bisects ∠ADC. Bisect means to cut in half.
∠ADC = 110° because it is double of ∠ADE.
Since AB║CD and AD║BC, the two sets of parallel lines means this shape is a parallelogram. In parallelograms, <u>opposite angles have equal measures</u>.
∠ADC = ∠CBE = 110°
All quadrilaterals have a sum of angles 360°. Since ∠DCB = ∠BAD and we know two of these other angles are each 110°:
360° - 2(110°) = 2(∠DCB)
∠DCB = 140°/2
∠DCB = ∠BAD = 70°
∠DCB was bisected by EC, which makes each divided part half.
∠DCE = ∠BCE = (1/2)(∠DCB)
∠DCE = ∠BCE = (1/2)(70°)
∠DCE = ∠BCE = 35°
All triangles' angles sum to 180°.
In ΔBCE, ∠BCE = 35° and ∠CBE = 110°.
∠CEB = 180° - (∠BCE + ∠CBE)
∠CEB = 180° - (35° + 110°)
∠CEB = 55°
Therefore m∠CEB is 55°.
Answer: 84.728
Step-by-step explanation: 105.91•.20=21.182
105.91-21.182=84.728
If you have any questions just ask
The Answer is A, verified apex
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➷ Adjacent angles total to 180 degrees
15x + 1 + 13x + 3 + 64 = 180
28x + 68 = 180
Subtract 68 from both sides:
18x = 112
Divide both sides by 28:
x = 4
Substitute this value back in:
15(4) + 1 = 61
Angle VTS = 61 degrees
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The first one:
5v + 3 = 5v - 5
Subtract 5v from both sides ->
3 = -5
This isn't true so that means there are no solutions...