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3 years ago

Select the correct answer.

Mathematics

1 answer:

diamong [38]3 years ago

8 0

Answer:

1 solution

Step-by-step explanation:

y=16, r=-21/2

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True or False: Receipts are a way to document or keep track of your expenses.

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Answer:

True

Step-by-step explanation:

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3 years ago

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4 years ago

Find the volume of a pyramid with a square base, where the side length of the base is 10.9 m and the height of the pyramid is 4.

natita [175]

Answer:

$V=186.1\ m^3$

Step-by-step explanation:

Volume of a Pyramid

The volume of a pyramid with base area Ab and height H is given by:

$\displaystyle V=\frac{A_b*H}{3}$

If the base is a square of side length L, then its area is:

$A_b=L^2$

Thus, substituting the above equation in the first:

$\displaystyle V=\frac{L^2*H}{3}$

The side length is L=10.9 m and the height is 4.7 m, thus the volume is:

$\displaystyle V=\frac{10.9^2*4.7}{3}$

$\displaystyle V=\frac{558.407}{3}$

$\boxed{V=186.1\ m^3}$

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4 years ago

The vargas family is hiking a 23 1/3 mile trail. the first day, they hiked 10 1/2 miles. how much further do they have to go to

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3 years ago

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,

professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so $\mu = 7*0.6 = 4.2$

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150$

$P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630$

$P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103$

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0

3 years ago