Answer:
7 - 9 + (9 - 5)^2 - 4 (-6/6) + 8 - 3×10
-4
If sandy has 8 and alex has 6 fewer than alex has 2. Since Jill has 2 then you add 8 plus 2 plus 2 which equals 12. So there is 12 all together
The number line would have an open circle that would be on 5 and the line would go right. the number line should count up.
Answer:
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.
First six not defective, each with 0.98 probability.
7th defective, with 0.02 probability. So

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
Find the expected number and variance of the number of components tested before a defective component is found.
Inverse binomial distribution, with 
Expected number before 1 defective(n = 1). So

Variance is:

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.