Answer:
Step-by-step explanation:
Nice summary problem.
<AEC
- AEC = 360 - 243.5 = 116.5
- The number of degrees in 1 rotation of a circle = 360o. You have accounted for 243.5 degrees. What is left over is the answer.
<EAD and <ECD
Both of these are tangents to a circle. Tangents meet radii at 90 degree angles.
<EAD = <ECD = 90 degrees
<ABC
<ABC is 1/2 the central angle. The Central angle is <AEC
- < AEC = 116.5
- <ABC = 1/2 * 116.5
- <ABC = 58.25
<ADC
There are 2 ways of doing this. You should know both of them.
<em><u>One</u></em>
All quadrilaterals = 360 degrees. You know three of the angles. You should be able to find ADC
- <ADC + 90 + 90 + 116.5 = 360 Add the four angles together.
- <ADC + 296.5 = 360 Combine terms on the left
- <ADC = 360 - 296.5 Subtract 238.25 from both sides
- <ADC = 63.5 Answer
<em><u>Method Two</u></em>
<ADC = 1/2 (major Arc - Minor Arc) This formula is fundamental to circle / tangent properties. The Major arc is the larger of the two parts of the circumference of a circle. The Minor arc is the smaller.
- <ADC = 1/2(243.5 - 116.5)
- <ADC = 1/2(127)
- <ADC = 63.5
Elimination:
7x - 3y = 20
5x + 3y = 16
(add)
12x = 36
÷ 12
x = 3
(5 × 3) + 3y = 16
15 + 3y = 16
- 15
3y = 1
÷ 3
y = 1/3
Substitution:
5x + 3y = 16
- 3y
5x = 16 - 3y
÷ 5
x = 3.2 - 0.6y
5(3.2 - 0.6y) + 3y = 16
16 - 3y + 3y = 16
16 = 16
- 16
6y = 0
÷ 6
y = 0
Sorry the substitution messed up for some reason, I'll fix it after I've answered the other question
Answer:
43
Step-by-step explanation:
Answer:
y = -3x - 11
Step-by-step explanation:
Use the given slope and point in the point-slope equation. Solving this will give us the y-intercept equation.
Point-slope formula: y - y = m(x - x)
Plug in the slope and point
y - (-5) = -3(x - (-2))
Subtracting negatives will make them positive. Multiply out the -3 to what is in the parentheses.
y + 5 = -3x - 6
Subtract the 5 from both sides
y = -3x - 11
The equation of the line is y = -3x - 11
9.2x10^-8
Move the decimal to the right 8 times. Since it is moved to the right, the exponent is negative.