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3 years ago

What is the average rate of change of f(x) = −2x + 1 from x = −5 to x = 1?

1 answer:

3 0

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)=-2x+1 \qquad 
\begin{cases}
x_1=-5\\
x_2=1
\end{cases}\implies \cfrac{f(1)-f(-5)}{-5-1}
\\\\\\
\cfrac{[-2(1)+1]~~-~~[-2(-5)+1]}{-6}\implies \cfrac{[-1]~~-~~[11]}{-6}
\\\\\\
\cfrac{-12}{-6}\implies 2$

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What is a simplified eCarlotta thinks that 3y + 5y3 is the same as 8y4. Which statement shows that it is NOT the same?Xpression

stira [4]

Questions:

(a) What is a simplified expression for (x + y) – (x – y)?

(b) Carlotta thinks that $3y + 5y^3$ is the same as $8y^4$ . Which statement shows that it is NOT the same?

Answer:

$(x + y) - (x - y) =2y$

$3y + 5y^3 \ne 8y^4$

Step-by-step explanation:

Solving (a):

Given

$(x + y) - (x - y)$

Required

Simplify

$(x + y) - (x - y)$

Open brackets

$(x + y) - (x - y) = x + y - x + y$

Collect Like Terms

$(x + y) - (x - y) = x - x+ y + y$

$(x + y) - (x - y) = y + y$

$(x + y) - (x - y) =2y$

Solving (b):

Given

$3y + 5y^3$ and $8y^4$

Required

Which expression shows they are not the same

The expression that shows this is:

$3y + 5y^3 \ne 8y^4$

Take for instance; y=2

Substitute 2 for y in $3y + 5y^3 \ne 8y^4$

$3*2 + 5*2^3 \ne 8*2^4$

Evaluate all exponents

$9 + 5*8 \ne 8*16$

$9 + 40 \ne 128$

$49 \ne 128$

The above expression supports $3y + 5y^3 \ne 8y^4$

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2 years ago

2.2f+0.3f−13−4= Pls hurry!

Aleks [24]

Answer:

-14.5

Step-by-step explanation:

To get the calculator and type 2.2+0.3-13-4

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2 years ago

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Tatiana [17]

1/3 is answer. Hope it helps

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3 years ago

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Monica [59]

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3 years ago

Of a total of 100 buses operated within a particular town, 48 usually run on time and 36 of these buses are owned by Jerry. Of t

miv72 [106K]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below is similar question:

48 out of 100 private buses usually run on time. Out of the buses that are on time, only 36 are owned by Jerry. Out of the remaining 52 buses that usually run late, only 7 are owned by Jerry. What is the probability that a bus is owned by Jerry, given that it runs on time?
A. 0.58
B. 0.67
C. 0.75
D. 0.81

The answer is C as 36/48 = .75

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3 years ago

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