Answer:
yes cuz my butt is phat
Step-by-step explanation:
Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
Answer:
Step-by-step explanation:
step 1
Find the area of the circle
The area of the circle is equal to
we have
substitute
step 2
we know that
The area of a circle subtends a central angle of 2π radians
so
using proportion
Find out the area of a sector with a central angle of 8 π/11 radians
Answer:
a² + b² = c²
13² + 13² = c²
169 + 169 = c²
338 = c²
c = √338 or 18.385 or 13√2
Answer:
Step-by-step explanation: Since the given problem states that the two angles, angle 1 and angle 2 form a linear pair, this means that they form a 180° line, so that:
measure angle 1 + measure angle 2 = 180°
Since measure of angle 2 is six more than twice the measure of angle 1, therefore:
measure angle 2 = 2 (measure angle 1) + 6
hence, substituting this into the first equation:
measure angle 1 + 2 (measure angle 1) + 6 = 180
3 (measure angle 1) = 174
measure angle 1 = 58°
Therefore,
measure angle 2 = 2 (measure angle 1) + 6
measure angle 2 = 2 (58°) + 6
measure angle 2 = 122*
