X+9=27
X=27-9
X=18
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At the start they both have 200?
If you mean <u>6²</u>
2(3)+4 that would be <u>36
</u> 10 or 3.6
<u>
</u>If you mean 6²/2(3)+4 then 36/2=18 x 3= 54 +4=58 (following order of operation)
If you meant the first example I did, I would have rewritten it as
6² ÷ (2x3+4)= for clarity. That would force me to do what is in parentheses first.
<u>
</u><u>
</u>
Answer:
4
Step-by-step explanation:
9991 = 97×103
The greatest prime factor of 9991 is 103. The sum of digits of 103 is 1+0+3 = 4.
First join the log4 on the left:
log4( x*(x-3) = log4(-7x+21)
Then x = -7, works: -7*(-10)=70 = -7*(-7)+21
x=-3, 18 = 42, does not work
x=3 0=0 works,
However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.
Now x=3 gives log4(0) on the left and right, which does not exist.
So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
