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3 years ago

Translate the inequality and solve. Negative three times a number is less than six.

Mathematics

2 answers:

luda_lava [24]3 years ago

7 0

Answer:

x<-18

Step-by-step explanation:

mart [117]3 years ago

4 0

Answer:

x>-2

Step-by-step explanation:

The translated inequality to be solved is -3x<6

You divide -3 by both sides which switches the sign because it is negative, there fore the answer is x>-2.

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1.6022x 10-19 round three decimal places

den301095 [7]

Answer:

1.6022x 10-19

Step-by-step explanation:

1.6022x 10-19 then simplifies into 16.022 because of the 10, and then the final answer is -2.978

6 0

3 years ago

Read 2 more answers

[1x-6]>1 what are the solutions

a_sh-v [17]

Answer:

x > 7

(I think this is Right but not sure yet )

3 0

3 years ago

Patty says that if you add the same negative integer five times, the sign of the sum is negative and its size is five times the

Elanso [62]

Her statement is true because multiplication is repeating addition

8 0

2 years ago

Which of the following shows the correct evaluation for the exponential expression 2 over 3 to the power of 5?

Allushta [10]

Answer:

its c 54

Step-by-step explanation:

7 0

3 years ago

Find the sum \[\sum_{k = 1}^{2004} \frac{1}{1 + \tan^2 (\frac{k \pi}{2 \cdot 2005})}.\]

vampirchik [111]

Answer:1002

Step-by-step explanation:

$\Rightarrow \sum_{k=1}^{2004}\left ( \frac{1}{1+\tan ^2\left ( \frac{k\pi }{2\cdot 2005}\right )}\right )$

and $1+\tan ^2\theta =\sec^2\theta$

and $\cos \theta =\frac{1}{\sec \theta }$

$\Rightarrow \sum_{k=1}^{2004}\left ( \cos^2\frac{k\pi }{2\cdot 2005}\right )$

as $\cos ^2\theta =\cos ^2(\pi -\theta )$

Applying this we get

$\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]$

every $\theta$ there exist $\pi -\theta$

such that $\sin^2\theta +\cos^2\theta =1$

therefore

$\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]=1002$

6 0

3 years ago