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marishachu [46]
3 years ago
8

What is the answer to the question

Mathematics
1 answer:
TiliK225 [7]3 years ago
6 0

Answer:

368in. or 184in^2

Step-by-step explanation:

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Write an equation in point-slope form for the line that satisfies the given set slope of 4/5, passes through (10,-30
hodyreva [135]

Answer:

y + 30 = 4/5(x - 10)

Step-by-step explanation:

Given the slope, 4/5, and point (10, -30):

We can plug these values into the point-slope form:

y - y1 = m(x - x1)

Let (x1, y1) = (10, -30)

and m = 4/5

y - (-30) = 4/5(x - 10)

y + 30 = 4/5(x - 10)

Therefore, the point-slope form is y + 30 = 4/5(x - 10)  

7 0
3 years ago
What is 9x-5-8+x= what
Elanso [62]
Hi there!

First you simplify.

Simplified = 9x+(−5)+(−8)+x

Then you combine the like terms.

<span><span><span><span><span>9x</span>+(<span>−5)</span></span>+(<span>−8)</span></span>+x (*-5 and -8 are like terms) (9x and x are like terms)

</span></span><span><span><span>Combined it's~ (<span><span>9x</span>+x</span>)</span>+<span>(<span><span>−5</span>+<span>−8</span></span>)

</span></span></span><span><span><span>Solve and that comes to 10x</span>+<span>−<span>13 which is your answer. :)

Hope this helps. 

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3 0
3 years ago
The base of a triangle is nine centimeters longer than the perpendicular height. If the area of the triangle is 180 square centi
Rom4ik [11]

Answer:

<em>The base is 24 cm long.</em>

Step-by-step explanation:

<u>Equations</u>

Let's call

b= base of the triangle

h=height of the triangle

The base is 9 cm longer than the height, thus:

b = h + 9

The area of the triangle is:

\displaystyle A=\frac{bh}{2}

\displaystyle A=\frac{(h+9)h}{2}

And its value is 180:

\displaystyle \frac{(h+9)h}{2}=180

Multiplying by 2:

(h+9)h=360

Operating:

h^2+9h-360=0

Factoring:

(h-15)(h+24)=0

The only valid positive solution is:

h = 15 cm

And b = h + 9 = 24

b = 24 cm

The base is 24 cm long.

7 0
3 years ago
Divide 30 in a ratio of 3:2
Sergeeva-Olga [200]
Other\ method:\\\\x;y-searches\\\\  \left\{\begin{array}{ccc}x+y=30&|subtract\ y\ from\ both\ sides\\x:y=3:2\end{array}\right\\\left\{\begin{array}{ccc}x=30-y&(1)\\\frac{x}{y}=\frac{3}{2}&(2)\end{array}\right\\\\subtitute\ (1)\ to\ (2):\\\\\frac{30-y}{y}=\frac{3}{2}\ \ \ \ |cross\ multiply\\\\(3)(y)=(2)(30-y)\\3y=60-2y\ \ \ \ |add\ 2y\ to\ both\ sides\\5y=60\ \ \ \ |divide\ both\ sides\ by\ 5\\\boxed{y=12}

Put\ the\ value\ of\ y\ to\ (1):\\x=30-12\\\boxed{x=18}\\\\Answer:\boxed{\left\{\begin{array}{ccc}x=18\\y=12\end{array}\right\to18:12}
4 0
3 years ago
Read 2 more answers
)
aleksandr82 [10.1K]
A: 292892 b: 2972 c: 9272726: d: 196373
6 0
3 years ago
Read 2 more answers
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