That would be the number in front of the variables
That is -24.
Ita A
Substitute with the value of n in the equation to get m as follows:
at n=1:
2m=-6(1)-5=-6-5=-11
m = -11/2
at n=2:
2m=-6(2)-5=-12-5=-17
m = -17/2
at n=3:
2m=-6(3)-5=-18-5=-23
m = -23/2
Answer:
Equation to determine crystals total bill (T) =(7.7+2x) - 1.50
Step-by-step explanation:
Given:
Number of bottles of pop purchased = 4
Number of candy bars purchased = 3
Number of chips bag purchased = 2
Cost of per bottle of pop = $1.25
Cost of per candy bar = $.90
Cost of the coupon = $1.50
To Find :
Equation to determine crystals total bill (T) given the cost of one bag of chips = ?
Solution:
Let the cost of one chips bag be x
Cost of 4 bottles of pop
=>
=>$ 5
Cost of 3 candy bars
=>
=>$ 2.7
Cost of 2 bags of chips
=>
=>$ 2x
Now the total cost of the bill is
T = 5 + 2.7+ 2x
T =7.7+2x
Also Krystal had a coupon worth $1.50, the cost of the ticket will be
T =(7.7+2x) - 1.50
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
mamaluj [8]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
<h2>Option A = 1*3 = 3 unit² </h2>
<h3>Distance between f and G = distance between E and H </h3>
F = (3,7)
G = (6,4)
H = (5,3)
E= (2,6)
= (3 units)
<h3>
Distance between FE = GH </h3>
= 1 units
Area = 3* 1
= 3 units²
