A water pipe leak floods 50 square feet every 1/5 minute. what is the flooded area after 6 minutes.

2 answers:

3 0

$\bf \begin{array}{ccll} ft^2&minute\\ \cline{1-2} 50&\frac{1}{5}\\\\ x&6 \end{array}\implies \cfrac{50}{x}=\cfrac{~~\frac{1}{5}~~}{6}\implies \cfrac{50}{x}=\cfrac{~~\frac{1}{5}~~}{\frac{6}{1}}\implies \cfrac{50}{x}=\cfrac{1}{5}\cdot \cfrac{1}{6} \\\\\\ \cfrac{50}{x}=\cfrac{1}{30}\implies 1500=x$

Crazy boy [7]3 years ago

3 0

Answer:

60 square feet.

Step-by-step explanation:

Given : a water pipe leak floods 50 square feet every 1/5 minute.

To find : what is the flooded area after 6 minutes.

Solution : We have given

In $\frac{1}{5}$ minute water pipe leak flood = 50 square feet.

In 1 minute water pipe leak flood = 50 * $\frac{1}{5]$ .

In 1 minute water pipe leak flood = 50 * $\frac{1}{5}$ * 6 square feet.

In 1 minute water pipe leak flood = 10 * 6 square feet.

In 1 minute water pipe leak flood = 60 square feet.

Therefore,

60 square feet.

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Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$