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3 years ago

Write the standard equation of the circle below.

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

7 0

Answer:

The first answer is correct.

(x + 1)^2 + (y - 2)^2 = 1

A circle with the midpoint M(Mx, My) and the radius r can be written as

(x - Mx)^2 + (y - My)^2 = r^2

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Which expression is equal to (6x−4)(3x−1)?

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Answer:

$(6x-4)(3x-1) = 18x^2 - 18x + 4$ is the required simplification.

Step-by-step explanation:

Here, the given expression is (6x−4)(3x−1).

By DISTRIBUTIVE PROPERTY of numbers:

A ( B + C ) = AB + AC

Simplifying the given expression, we get:

$(6x-4)(3x-1) = 6x(3x-1)-4(3x-1)\\= 6x(3x) -1(6x) -4(3x) +4\\=18x^2 - 6x - 12x + 4\\18x^2 - 18x + 4$

or, $(6x-4)(3x-1) = 18x^2 - 18x + 4$

Hence the given expression is simplified.

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